CODEWITHSUNDEEP
c++command-line-argumentsargv
Taylor
Taylor

Reputation: 123

Why is my command line argument handling crashing my program?

Why is something so seemingly simple is crashing my program?

I am trying to get a value for n to make an array the size of N and perform various operations on it, but that's beside the point. Anyways, It keeps crashing every time I try to access argv[1].

int main(int argc, char * argv[])
{
  int n;
  n = atoi(argv[1]); //Crashes here!
  cout << "\nN: " << n << endl;
}

Upvotes: 0

Views: 1321

Answers (1)

Joshua
Joshua

Reputation: 441

Does argv[1] exist? To prevent your code from accessing memory it should not check how many arguments were passed.

if(argc >= 2)
  n = argv[1];
else
  std::cout << "Proper usage: .....\n";

This seems like a great time to learn how to use your debugger to view the contents of argv and argc.

Upvotes: 1

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