CODEWITHSUNDEEP
jqueryoopobjectmultidimensional-arraystructure
Mitesh Sharma
Mitesh Sharma

Reputation: 261

Using OO concept in jQuery, using function() and creating array of structure

This is regarding using OO concepts in jQuery.

I want to create an array of structures in jQuery so that I can save a char and an integer in same the element of an array.

I want to store 'Y' and 2 in each element of array, so that I can change the value of the integer based on whether the value of the char is 'Y'.

I have the following code

        var arrOfArr = new Array(3);
        for (var x = 0; x < arrOfArr.length; x++) {
            arrOfArr[x] = [new struct('Y', 0),new struct('Y', 0),new struct('Y', 0)];
        }

        function struct($user, $turnCount) {
            var user = $user;
            var turnCount = $turnCount;
        }

Now when I call alert(arrOfArr[0][0].turnCount), it is giving undefined. But if I define arrOfArr[0][0].turnCount = 0 and again call the same alert it gives me 0.

Can you please help me understand how can I initialize an array of structures at the time of initialization?

Upvotes: 2

Views: 271

Answers (2)

David Barker
David Barker

Reputation: 14620

var user

and

var turnCount

are private variables to structs scope

try using 

this.user = $user;
this.turnCount = $turncount;

Upvotes: 1

Fr&#233;d&#233;ric Hamidi
Fr&#233;d&#233;ric Hamidi

Reputation: 262939

You're assigning to local variables instead of instance properties in your constructor.

Try writing:

function struct($user, $turnCount) {
    this.user = $user;
    this.turnCount = $turnCount;
}

Upvotes: 3

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