CODEWITHSUNDEEP
javaregex
diez
diez

Reputation: 125

what is the right regex?

I try to find a regex in order to extract the name of a file. My String is path/string.mystring

for exemple 

totot/tototo/tatata.tititi/./com.myString

I try to get myString.

I tried String[] test = foo.split("[*.//./.]");

Upvotes: 0

Views: 96

Answers (7)

A human being
A human being

Reputation: 1220

Try this code:

import java.util.regex.Pattern;
import java.util.regex.Matcher;

public class Regexp
{
    public static void main(String args[]) 
    {
    String x = "totot/tototo/tatata.tititi/./com.myString";
    Pattern pattern = Pattern.compile( "[a-z0-9A-Z]+$");
    Matcher matcher = pattern.matcher(x);

    while (matcher.find()) 
        {
        System.out.format("Text found in x: => \"%s\"\n",
                  matcher.group(0));
        }
    }
}

Upvotes: 0

codebox
codebox

Reputation: 20254

A similar question has been answered here. I would say that using a regex to get the file name is the wrong way to go (for example, if your code ever tries to run against a Windows file path the slashes in your regex will be the wrong way round) - why not just use:

new File(fileName).getName();

to get the name of the file, and then extract the part of the file name that you want using a simpler split:

String[] fileNameParts = foo.split("\\.");
String partThatYouWant = fileNameParts [fileNameParts.length - 1];

Upvotes: 1

Rodrigo Sasaki
Rodrigo Sasaki

Reputation: 7226

Maybe you should just use the String API. Something like this:

public static void main(String[] args){
    String path = "totot/tototo/tatata.tititi/./com.myString";
    System.out.println(path.substring(path.lastIndexOf(".") + 1));
}

Does it fit your case? There are many problems in working with indexes. But if you're always sure there will be a . you can use this without any problems.

Upvotes: 0

PermGenError
PermGenError

Reputation: 46408

A non-regex solution using String#subString& String#lastIndexOf would be. 

String path="totot/tototo/tatata.tititi/./com.myString";
String name = path.substring(path.lastIndexOf(".")+1);

Upvotes: 0

Kent
Kent

Reputation: 195059

My String is path/string.mystring

If your string pattern is fixed following the rule above, how about:

string.replaceAll(".*\\.","")

Upvotes: 0

user21033168
user21033168

Reputation: 444

You can get the last word with this: \w+$

Upvotes: 1

Ted Hopp
Ted Hopp

Reputation: 234795

If you want to split on period or slash, the regex should be

foo.split("[/\\.]")

Alternatively, you could do this:

String name = foo.substring(foo.lastIndexOf('.') + 1);

Upvotes: 0

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