CODEWITHSUNDEEP
javascriptjqueryjquery-deferred
Steve P
Steve P

Reputation: 19377

Ignore timeouts during jQuery.when

I have some jQuery ajax requests which I am running in parallel with a .when call. I want to ignore the ones that haven't returned after their timeout period.

Here is a simple form of it:

var ajax1 = $.ajax({url: url1,
    timeout: 1000,
    success: function() {
        console.log("1 done");
    }
});

var ajax2 = $.ajax({url: url2,
    timeout: 1000,
    success: function() {
        console.log("2 done");
    }
});

$.when(ajax1, ajax2).done(function() {
    console.log("all done");
});

In the above example, if url1 doesn't respond without 1 second, I still want to reach the "all done". I know how to trap the timeout error in each ajax call, but I don't know how to flag the error as ignored.

Upvotes: 0

Views: 109

Answers (1)

jfriend00
jfriend00

Reputation: 707248

Can't you just use .always() instead of .done() if you want all ways (success, error, timeout, etc...) that the ajax call is finished instead of just successful ways it finishes:

$.when(ajax1, ajax2).always(function() {
    console.log("all done");
});

The arguments passed to the .always() callback can be used to determine success or type of error from the ajax calls.

Upvotes: 4

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