Reputation: 39
I would like to build on the answer I found here: Bash script to find specific files in a hierarchy of files
find $dir -name $name -exec scp {} $destination \;
I have a file with a list of file names and I need to find those files on a backup disk, then copy those files found to a destination folder, and lastly print the files that could not be found to a new file.
the last step would be helpful so that I wouldn't need to make another list of files copied and then do a compare with original list.
If the script can then make a list of the copied files, and do a compare, then print the differences, then that's exactly what's required. Unless the shell process find can print to file each time it "Can't find" a file.
Upvotes: 1
Views: 9312
Reputation: 141
Assuming that your list is separated by newlines; something like this should work
#!/bin/bash
dir=someWhere
dest=someWhereElse
toCopyList=filesomewhere
notCopied=filesomewhereElse
while read line; do
find "$dir" -name "$line" -exec cp '{}' $dest \; -printf "%f\n"
done < "$toCopyList" > cpList
#sed -i 's#'$dir'/##' cpList
# I used # instead of / in sed to not confuse sed with / in $dir
# Also, I assumed the string in $dir doesnot end with a /
cat cpList "$toCopyList" | sort | uniq -c | sed -nr '/^ +1/s/^ +1 +(.*)/\1/p' > "$notCopied"
# Will not work if you give wild cards in your "toCopyList"
Hope it helps
Upvotes: 2
Reputation: 51613
while read fname ; do
find /FROM/WHERE/TO/COPY/ \
-type f \
-name "$fname" \
-exec cp \{\} /DESTINATION/DIR/ \; 2>/dev/null
find /DESTINATION/DIR/ \
-type f \
-name "$fname" &>/dev/null || \
echo $fname
done < FILESTOCOPY > MISSEDFILES
Will do.
Upvotes: 0