Reputation: 8302
Lets say I have my first Point struct:
Point start = new Point(1, 9);
and my second:
Point end = new Point(4, 9);
I want to get all the points between the start and end. So for example I would want 2,9 and 3,9 in an array. Does .NET have something built in for this?
Upvotes: 9
Views: 16819
Reputation: 301
You can get between points using below code. User just need to define that how many points to get between two points. Here I defined as 10 points.
PointF pStart = new PointF(10, 10);
PointF pEnd = new PointF(100, 100);
PointF[] betPoints = new PointF[10];
for (int i = 1; i <= 10; i++)
{
betPoints[i].X = (Math.Abs(pStart.X - pEnd.X) / 10) * i + pEnd.X;
betPoints[i].Y = (Math.Abs(pStart.Y - pEnd.Y) / 10) * i + pEnd.Y;
}
Upvotes: 0
Reputation: 21
I know it's been quite a long time since you first asked this question but I was looking for something similar recently and found this wiki (https://en.wikipedia.org/wiki/Bresenham%27s_line_algorithm), which contained pseudo code.
So I've implemented a function with the pseudo code to perform this calculation and add the points to a List.
public List<Point> GetPoints(Point p1, Point p2)
{
List<Point> points = new List<Point>();
// no slope (vertical line)
if (p1.X == p2.X)
{
for (double y = p1.Y; y <= p2.Y; y++)
{
Point p = new Point(p1.X, y);
points.Add(p);
}
}
else
{
// swap p1 and p2 if p2.X < p1.X
if (p2.X < p1.X)
{
Point temp = p1;
p1 = p2;
p2 = temp;
}
double deltaX = p2.X - p1.X;
double deltaY = p2.Y - p1.Y;
double error = -1.0f;
double deltaErr = Math.Abs(deltaY / deltaX);
double y = p1.Y;
for (double x = p1.X; x <= p2.X; x++)
{
Point p = new Point(x, y);
points.Add(p);
Debug.WriteLine("Added Point: " + p.X.ToString() + "," + p.Y.ToString());
error += deltaErr;
Debug.WriteLine("Error is now: " + error.ToString());
while (error >= 0.0f)
{
Debug.WriteLine(" Moving Y to " + y.ToString());
y++;
points.Add(new Point(x, y));
error -= 1.0f;
}
}
if (points.Last() != p2)
{
int index = points.IndexOf(p2);
points.RemoveRange(index + 1, points.Count - index - 1);
}
}
return points;
}
Upvotes: 2
Reputation: 434
This is what I ended up doing. As @Cody Gray mentioned in his comment, there are infinite points on a line. So you need to specify how many points you are looking to retrieve.
My Line class:
public class Line {
public Point p1, p2;
public Line(Point p1, Point p2) {
this.p1 = p1;
this.p2 = p2;
}
public Point[] getPoints(int quantity) {
var points = new Point[quantity];
int ydiff = p2.Y - p1.Y, xdiff = p2.X - p1.X;
double slope = (double)(p2.Y - p1.Y) / (p2.X - p1.X);
double x, y;
--quantity;
for (double i = 0; i < quantity; i++) {
y = slope == 0 ? 0 : ydiff * (i / quantity);
x = slope == 0 ? xdiff * (i / quantity) : y / slope;
points[(int)i] = new Point((int)Math.Round(x) + p1.X, (int)Math.Round(y) + p1.Y);
}
points[quantity] = p2;
return points;
}
}
Usage:
var line = new Line(new Point(10, 15), new Point(297, 316));
var points = line.getPoints(20);
That will return a Point array of 20 Points evenly spaced between the two endpoints (inclusive). Hope that helps!
Upvotes: 14
Reputation: 1436
There are no build in functions for this, since there are no points between points. Mathematicaly there is a line between two points. In terms of Computer-Graphics, lines could be antialiased and so beeing not rounded to full Integer numbers.
If you are looking for a fast method of creating all integral numbers inbetween, I guess Bresenhams-Line-Algorithm would be your choice. But this is not build into .NET, you have to code it by yourself (or take Matthew Watson's implementation):
http://en.wikipedia.org/wiki/Bresenham's_line_algorithm
There are even fasther algorithms for doing it, but I would go for Bresenham.
Upvotes: 9