CODEWITHSUNDEEP
javarestjaxb
User1
User1

Reputation: 41251

Using JAXB to unmarshal/marshal a List<String>

I'm trying to create a very simple REST server. I just have a test method that will return a List of Strings. Here's the code:


@GET
@Path("/test2")
public List test2(){
    List list=new Vector();
    list.add("a");
    list.add("b");
    return list;
}

It gives the following error:

SEVERE: A message body writer for Java type,
class java.util.Vector, and MIME media type,
application/octet-stream, was not found

I was hoping JAXB had a default setting for simple types like String, Integer, etc. I guess not. Here's what I imagined:


<Strings>
  <String>a</String>
  <String>b</String>
</Strings>

What's the easiest way to make this method work?

Upvotes: 47

Views: 131244

Answers (12)

Gonen I
Gonen I

Reputation: 6127

For a more general solution, for JAXB-XML serialization of any top level list , which only requires 1 new class to be written, check out the solution given in this question:

Is it possible to programmatically configure JAXB?

public class Wrapper<T> {

private List<T> items = new ArrayList<T>();

@XmlAnyElement(lax=true)
public List<T> getItems() {
    return items;
}

}

//JAXBContext is thread safe and so create it in constructor or 
//setter or wherever:
... 
JAXBContext jc = JAXBContext.newInstance(Wrapper.class, clazz);
... 

public String marshal(List<T> things, Class clazz) {

  //configure JAXB and marshaller     
  Marshaller m = jc.createMarshaller();
  m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

  //Create wrapper based on generic list of objects
  Wrapper<T> wrapper = new Wrapper<T>(things);
  JAXBElement<Wrapper> wrapperJAXBElement = new JAXBElement<Wrapper>(new QName(clazz.getSimpleName().toLowerCase()+"s"), Wrapper.class, wrapper);

  StringWriter result = new StringWriter();
  //marshal!
  m.marshal(wrapperJAXBElement, result);

  return result.toString();

}

Upvotes: 0

Alex Abdugafarov
Alex Abdugafarov

Reputation: 6432

This can be done MUCH easier using wonderful XStream library. No wrappers, no annotations.

Target XML

<Strings>
  <String>a</String>
  <String>b</String>
</Strings>

Serialization

(String alias can be avoided by using lowercase string tag, but I used OP's code)

List <String> list = new ArrayList <String>();
list.add("a");
list.add("b");

XStream xStream = new XStream();
xStream.alias("Strings", List.class);
xStream.alias("String", String.class);
String result = xStream.toXML(list);

Deserialization

Deserialization into ArrayList 

XStream xStream = new XStream();
xStream.alias("Strings", ArrayList.class);
xStream.alias("String", String.class);
xStream.addImplicitArray(ArrayList.class, "elementData");
List <String> result = (List <String>)xStream.fromXML(file);

Deserialization into String[]

XStream xStream = new XStream();
xStream.alias("Strings", String[].class);
xStream.alias("String", String.class);
String[] result = (String[])xStream.fromXML(file);

Note, that XStream instance is thread-safe and can be pre-configured, shrinking code amount to one-liners.

XStream can also be used as a default serialization mechanism for JAX-RS service. Example of plugging XStream in Jersey can be found here

Upvotes: 11

user7455210
user7455210

Reputation: 1

If you are using maven in the jersey project add below in pom.xml and update project dependencies so that Jaxb is able to detect model class and convert list to Media type application XML:

<dependency>
    <groupId>com.sun.xml.bind</groupId>
    <artifactId>jaxb-core</artifactId>
    <version>2.2.11</version>
</dependency>

Upvotes: 0

petrsyn
petrsyn

Reputation: 5116

Finally I've solved it using JacksonJaxbJsonProvider It requires few changes in your Spring context.xml and Maven pom.xml

In your Spring context.xml add JacksonJaxbJsonProvider to the <jaxrs:server>:

<jaxrs:server id="restService" address="/resource">
    <jaxrs:providers>
        <bean class="org.codehaus.jackson.jaxrs.JacksonJaxbJsonProvider"/>
    </jaxrs:providers>
</jaxrs:server>

In your Maven pom.xml add:

<dependency>
    <groupId>org.codehaus.jackson</groupId>
    <artifactId>jackson-jaxrs</artifactId>
    <version>1.9.0</version>
</dependency>

Upvotes: 3

mstrthealias
mstrthealias

Reputation: 2921

I would've saved time if I found Resteasy Jackson Provider sooner.

Just add the Resteasy Jackson Provider JAR. No entity wrappers. No XML annotations. No custom message body writers.

Upvotes: 0

Zounadire
Zounadire

Reputation: 1574

In case anyone of you wants to write a list wrapper for lists containing elements of multiple classes and want to give an individual XmlElement name according to the Class type without Writing X Wrapper classes you could use the @XmlMixed annotation. By doing so JAXB names the items of the list according to the value set by the @XmlRootElement. When doing so you have to specify which classes could possibly be in the list using @XmlSeeAlso

Example:

Possible Classes in the list

@XmlRootElement(name="user")
public class User {/*...*/}

@XmlRootElement(name="entry")
public class LogEntry {/*...*/}

Wrapper class

@XmlRootElement(name="records")
@XmlSeeAlso({User.class, LogEntry.class})
public static class JaxbList<T>{

    protected List<T> records;

    public JaxbList(){}

    public JaxbList(List<T> list){
        this.records=list;
    }

    @XmlMixed 
    public List<T> getRecords(){
        return records;
    }
}

Example:

List l = new List();
l.add(new User("userA"));
l.add(new LogEntry(new UserB()));


XStream xStream = new XStream();
String result = xStream.toXML(l);

Result:

<records>
    <user>...</user>
    <entry>...</entry>
</records>

Alternatevily you could specify the XmlElement names directly inside the wrapper class using the @XmlElementRef annotation

@XmlRootElement(name="records")
@XmlSeeAlso({User.class, LogEntry.class})
public static class JaxbList<T>{

    protected List<T> records;

    public JaxbList(){}

    public JaxbList(List<T> list){
        this.records=list;
    }

    @XmlElementRefs({
        @XmlElementRef(name="item", type=Object.class),
        @XmlElementRef(name="user", type=User.class),
        @XmlElementRef(name="entry", type=LogEntry.class)
    })
    public List<T> getRecords(){
        return records;
    }
}

Upvotes: 13

Maggy
Maggy

Reputation: 1

Make sure to add @XmlSeeAlso tag with your specific classes used inside JaxbList. It is very important else it throws HttpMessageNotWritableException

Upvotes: 0

J&#233;r&#244;me Verstrynge
J&#233;r&#244;me Verstrynge

Reputation: 59634

From a personal blog post, it is not necessary to create a specific JaxbList < T > object.

Assuming an object with a list of strings:

@XmlRootElement
public class ObjectWithList {

    private List<String> list;

    @XmlElementWrapper(name="MyList")
    @XmlElement
    public List<String> getList() {
        return list;
    }

    public void setList(List<String> list) {
        this.list = list;
    }

}

A JAXB round trip:

public static void simpleExample() throws JAXBException {

    List<String> l = new ArrayList<String>();
    l.add("Somewhere");
    l.add("This and that");
    l.add("Something");

    // Object with list
    ObjectWithList owl = new ObjectWithList();
    owl.setList(l);

    JAXBContext jc = JAXBContext.newInstance(ObjectWithList.class);
    ObjectWithList retr = marshallUnmarshall(owl, jc);

    for (String s : retr.getList()) {
        System.out.println(s);
    } System.out.println(" ");

}

Produces the following:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<objectWithList>
    <MyList>
        <list>Somewhere</list>
        <list>This and that</list>
        <list>Something</list>
    </MyList>
</objectWithList>

Upvotes: 12

Sample Code
Sample Code

Reputation: 329

@GET
@Path("/test2")
public Response test2(){
   List<String> list=new Vector<String>();
   list.add("a");
   list.add("b");

   final GenericEntity<List<String>> entity = new GenericEntity<List<String>>(list) { };
   return Response.ok().entity(entity).build();
}

Upvotes: 32

piepera
piepera

Reputation: 2113

User1's example worked well for me. But, as a warning, it won't work with anything other than simple String/Integer types, unless you add an @XmlSeeAlso annotation:

@XmlRootElement(name = "List")
@XmlSeeAlso(MovieTicket.class)
public class MovieTicketList {
    protected List<MovieTicket> list;

This works OK, although it prevents me from using a single generic list class across my entire application. It might also explain why this seemingly obvious class doesn't exist in the JAXB package.

Upvotes: 2

LiorH
LiorH

Reputation: 18824

I have encountered this pattern a few times, I found that the easiest way is to define an inner class with JaxB annotations. (anyways, you'll probably want to define the root tag name)

so your code would look something like this

@GET
@Path("/test2")
public Object test2(){
   MyResourceWrapper wrapper = new MyResourceWrapper();
   wrapper .add("a");
   wrapper .add("b");
   return wrapper ;
}

@XmlRootElement(name="MyResource")
private static class MyResourceWrapper {
       @XmlElement(name="Item")
       List<String> list=new ArrayList<String>();
       MyResourceWrapper (){}

       public void add(String s){ list.add(s);}
 }

if you work with javax.rs (jax-rs) I'd return Response object with the wrapper set as its entity

Upvotes: 8

User1
User1

Reputation: 41251

I used @LiorH's example and expanded it to:


@XmlRootElement(name="List")
public class JaxbList<T>{
    protected List<T> list;

    public JaxbList(){}

    public JaxbList(List<T> list){
        this.list=list;
    }

    @XmlElement(name="Item")
    public List<T> getList(){
        return list;
    }
}

Note, that it uses generics so you can use it with other classes than String. Now, the application code is simply:


    @GET
    @Path("/test2")
    public JaxbList test2(){
        List list=new Vector();
        list.add("a");
        list.add("b");
        return new JaxbList(list);
    }

Why doesn't this simple class exist in the JAXB package? Anyone see anything like it elsewhere?

Upvotes: 47

Related Questions