Reputation:
Working on an assignment involving Genetic Algorithms (loads of headaches, loads of fun). I need to be able to test differing crossover methods and differing mutation methods, to compare their results (part of the paper I have to write for the course). As such, I want to just pass the function names into the Repopulate method, as function handles.
function newpop = Repopulate(population, crossOverMethod, mutationMethod)
...
child = crossOverMethod(parent1, parent2, @mutationMethod);
...
function child = crossOverMethod(parent1, parent2, mutationMethod)
...
if (mutateThisChild == true)
child = mutationMethod(child);
end
...
The key point here is like 3, parameter 3: how do I pass mutationMethod down another level? If I use the @ symbol, I get told:
"mutationMethod" was previously used as a variable,
conflicting with its use here as the name of a function or command.
If I don't use the @ symbol, then mutationMethod gets called, with no parameters, and is quite unhappy.
While I am aware that yes, I could just rewrite my code to make it work differently, I'm now curious as to how to make it actually work.
Any help is greatly appreciated.
Upvotes: 10
Views: 11472
Reputation: 124573
Actually just dont use the @ symbol, use it when you call the Repopulate function instead. Example:
function x = fun1(a,m)
x = fun2(a,m);
end
function y = fun2(b,n)
y = n(b);
end
which we call as:
> fun1([1 2 3], @sum)
6
Refer to the documentation for Passing Function Handle Arguments
Note you can check if the argument is a function handle by: isa(m,'function_handle')
. Therefore you can make your function Repopulate more flexible by accepting both a function handle and a function name as a string:
function x = fun(a,m)
if ischar(m)
f = str2func(m);
elseif isa(m,'function_handle')
f = m;
else
error('expecting a function')
end
x = fun2(a,f);
end
which now can be called both ways:
fun1([1 2 3], @sum)
fun1([1 2 3], 'sum')
Upvotes: 13