Reputation: 27
I've seen this question asked before but I can't find an answer that helps me solve my problem. There's a few things happening here. This is displaying a menu that will allow the user to:
This information is saved to a data file that should be input and output to. I have a problem with the first menu option when trying to view the data in the file. Assume there is already a data file C:\danceexpenses.txt
containing this information:
DJ
100
Site
100
Food
100
Favors
100
Security
100
Ticket printing
100
Etc.
100
etc.
100
The program will not display the information. It only gives a blank line for each. Is there something I need to add to configure the output?
void charges()
{
//Structures to hold data
struct Expenses
{
string name;
double cost;
};
int chargesChoice;
const int CHARGES_MENU_VIEW = 1, CHARGES_MENU_UPDATE = 2, CHARGES_MENU_QUIT = 3;
const int NUM_EXPENSES = 8; //number of expenses
Expenses danceExpenses[NUM_EXPENSES]; //array of structures
int index; //loop counter
cout << "\nWhat would you like to do?\n\n"
<< "1. View charges\n"
<< "2. Update charges\n"
<< "3. Return to main menu\n"
<< "Enter your choice: ";
cin >> chargesChoice;
while (chargesChoice < CHARGES_MENU_VIEW || chargesChoice > CHARGES_MENU_QUIT)
{
cout << "\nPlease enter a valid menu choice: ";
cin >> chargesChoice;
}
switch (chargesChoice)
{
case CHARGES_MENU_VIEW: //Display the expenses data
myFile.open("c:\\danceexpenses.txt", ios::in); //open file
if (!myFile)
{
cout << "Error opening file. Program aborting.\n";
return;
}
char output[100];
cout << "\nHere are the expected expenses for the dance:\n";
for (index = 0; index < NUM_EXPENSES; index++)
cout << danceExpenses[index].name << endl << endl;
myFile.close(); //close file
break;
case CHARGES_MENU_UPDATE:
//get expense data
myFile.open("c:\\danceexpenses.txt", ios::out); //open file
if (!myFile)
{
cout << "Error opening file. Program aborting.\n";
return;
}
for (index = 0; index < NUM_EXPENSES; index++)
{
cout << "Enter the name of the expense: ";
cin.ignore();
getline(cin, danceExpenses[index].name);
cout << "Enter the expected cost for this expense: ";
cin >> danceExpenses[index].cost;
}
//Write data to file
for (index = 0; index < NUM_EXPENSES; index++)
{
myFile << danceExpenses[index].name << endl;
myFile << danceExpenses[index].cost << endl;
}
myFile.close(); //close file
break;
case CHARGES_MENU_QUIT:
showMenu();
break;
}
charges();
}
Upvotes: 0
Views: 4613
Reputation: 754900
If your first action is to enter 1, the code should enter:
case CHARGES_MENU_VIEW: //Display the expenses data
myFile.open("c:\\danceexpenses.txt", ios::in); //open file
if (!myFile)
{
cout << "Error opening file. Program aborting.\n";
return;
}
char output[100];
cout << "\nHere are the expected expenses for the dance:\n";
for (index = 0; index < NUM_EXPENSES; index++)
cout << danceExpenses[index].name << endl << endl;
myFile.close(); //close file
break;
This opens the dance expenses file, but doesn't read from it. It then iterates through a list of expenses that have not been initialized, and closes the input file. There's also an unused variable output
.
You need to read the data into memory before printing it out.
int num = 0;
while (myFile >> danceexpenses[num].name >> danceexpenses[num].cost)
num++;
for (index = 0; index < num; index++)
cout << danceExpenses[index].name << endl << endl;
Upvotes: 1