CODEWITHSUNDEEP
phpdateicalendarstrtotime
Solid I
Solid I

Reputation: 690

PHP - Formated Date to UNIX to iCal

I'm trying to format my stored dates 2013-04-23 19:00 to iCal format: 20130423T190000. Here's how I'm trying to do it:

$start = strtotime($event["event_start"]);
$start = date('Ymd\THis',$start);

This code returns 19691231T190000.

I thought that because the starting string is missing seconds, that could have been the problem, but after trying $start = strtotime($event["event_start"] . ":00"); I've ruled that out.

Upvotes: 1

Views: 551

Answers (2)

SH-
SH-

Reputation: 1642

cYou appear to be missing something. Are you sure $event["event_start"] is populated.

date('Ymd\THis',strtotime('2013-04-23 19:00')) == 20130423T190000

While

date('Ymd\THis',strtotime('')) == 19691231T190000

Check value of $event["event_start"].

EDIT: Hint was that 1969 is suspiciously close to UNIX epoch of 1970.

FROM marc b -> the difference was the timezone of UTC +5

Upvotes: 1

Christian-G
Christian-G

Reputation: 2361

Try this:

$str = "DTSTART;TZID=<your timezone>:".date('Ymd', strtotime($start));

See:

http://php.net/manual/en/timezones.php

Upvotes: 0

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