Reputation: 12712
I am having difficulty getting this sort to work. Current always has precedence over name. I can get it to sort on the values of either current or name but not both.
My array look like this.
var arr = [{current:true, name:"A name"},
{name:"A name"}, {name:"B name"},
{current:true, name:"B name"}];
arr.sort(sort_me)
Here's the sort function.
var sort_me = function(left, right){
var value = "name";
var sort_by_val = function(){
return left[value] == right[value] ? 0 : (left[value] < right[value] ? -1 : 1);
}
if(left.current===right.current) {
sort_by_val();
}else{
if(left.current===true){
return -1;
}else{
if(right.current===true){
return 1;
}else{
sort_by_val();
}
}
}
}
Upvotes: 0
Views: 2069
Reputation: 388406
Try
var sort_me = function(left, right) {
var value = "name";
var sort_by_val = function() {
return left[value] == right[value] ? 0 : (left[value] < right[value]
? -1
: 1);
}
if (left.current === right.current) {
return sort_by_val(); //missing return
} else {
if (left.current === true) {
return -1;
} else if (right.current === true) {
return 1;
} else {
return sort_by_val(); //missing return
}
}
}
Demo: Fiddle
Upvotes: 1
Reputation: 105905
You're missing a return
:
if(left.current===right.current) {
return sort_by_val();
}
Otherwise your return value will be undefined
if both current
s are set:
var sort_me = function(left, right){
var nameorder = left.name === right.name ? 0 : (left.name < right.name ? -1 : 1);
if(
(left.current && right.current) ||
(!left.current && !right.current)
) {
return nameorder;
} else if(left.current) {
return -1;
} else {
return 1;
}
}
Upvotes: 5