CODEWITHSUNDEEP
javascriptarrayssorting
Romain Braun
Romain Braun

Reputation: 3684

Sorting Array alphabetically, keeping numbers and special chars at the end

I'm sorting an Array alphabetically using this :

contactList.sort((function(index){
        return function(a, b){
            return (a[index] == b[index] ? 0 : (a[index] < b[index] ? -1 : 1));
        };
    })(2));

It works great, the only problem is that numbers and special characters appear at the top of my array. I would like it to be sorted alphabetically, but I also want it to store the numbers & special chars at the end.

I really have no idea how to modify my function in order to do this.

Upvotes: 0

Views: 1379

Answers (1)

kirilloid
kirilloid

Reputation: 14304

Just check, whether are they letters or not. I'm checking only first character, but maybe you'll need to extend this check for case a[index].charAt(0) == b[index].charAt(0) to compare following letters and so on in loop.

contactList.sort((function(index){
    return function(a, b){
        var aIsLetter = a[index].charAt(0).match(/[a-z]/i),
            bIsLetter = b[index].charAt(0).match(/[a-z]/i);
        if (aIsLetter && !bIsLetter) return -1;
        if (!aIsLetter && bIsLetter) return 1;
        return (a[index] == b[index] ? 0 : (a[index] < b[index] ? -1 : 1));
    };
})(2));

Upvotes: 2

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