CODEWITHSUNDEEP
pythonoutput
kate88
kate88

Reputation: 371

Writing printed output to a file (python)

I have a problem with writing my printed output to a file.

My code:

list1 = [2,3]
list2 = [4,5]
list3 = [6,7]

for (a, b, c) in zip(list1, list2, list3):
    print a,b,c

the output I get is:

>>> 
2 4 6
3 5 7
>>>

but I have problems with saving this output, I tried:

fileName = open('name.txt','w')
for (a, b, c) in zip(list1, list2, list3):
    fileName.write(a,b,c)

and various combinations like fileName.write(a+b+c) or (abc), but I am unsuccessful...

Cheers!

Upvotes: 0

Views: 285

Answers (4)

Eric
Eric

Reputation: 97571

You can use the print >> file syntax:

with open('name.txt','w') as f:
    for a, b, c in zip(list1, list2, list3):
        print >> f, a, b, c

Upvotes: 0

aldeb
aldeb

Reputation: 6828

The problem is that the write method expects a string, and your giving it an int.

Try using format and with:

with open('name.txt','w') as fileName:
    for t in zip(list1, list2, list3):
        fileName.write('{} {} {}'.format(*t))

Upvotes: 1

Inbar Rose
Inbar Rose

Reputation: 43447

Use with. Possibly your file handle is not closed, or flushed correctly and so the file is empty.

list1 = [2,3]
list2 = [4,5]
list3 = [6,7]

with open('name.txt', 'w') as f:
    for (a, b, c) in zip(list1, list2, list3):
        f.write(a, b, c)

You should also note that this will not create new lines at the end of each write. To have the contents of the file be identical to what you printed, you can use the following code (choose one write method):

with open('name.txt', 'w') as f:
    for (a, b, c) in zip(list1, list2, list3):
        # using '%s' 
        f.write('%s\n' % ' '.join((a, b, c)))
        # using ''.format()
        f.write('{}\n'.format(' '.join((a, b, c))))

Upvotes: 0

Some programmer dude
Some programmer dude

Reputation: 409166

How about using a format string:

fileName.write("%d %d %d" % (a, b, c))

Upvotes: 0

Related Questions