CODEWITHSUNDEEP
phparraysassign
Petja Zaichikov
Petja Zaichikov

Reputation: 283

assign one key of function output array to variable in tight away?

I need to make following in one line, i am looking for method of making similar code one line not to solve this particular example.

$file_path = pathinfo($_SERVER["SCRIPT_NAME"]);
$file_name = $file_path["filename"];

e.g.

$file_name = pathinfo($_SERVER["SCRIPT_NAME"])["filename"];

Upvotes: 2

Views: 48

Answers (2)

hek2mgl
hek2mgl

Reputation: 158130

Unfortunately PHP's syntax does not support this for versions lower than PHP5.5. As of PHP5.5 you can just write:

echo pathinfo($path)['filename'];

If you are working with a version < 5.5, I would suggest to write a custom function:

function array_get($key, $array) {
    if(!array_kex_exists($key, $array)) {
        throw new Exception('$array has no index: ' . $key);
    }
    return $array[$key];
}

Then use it:

$filename = array_get('filename', pathinfo($path));

Upvotes: 0

raidenace
raidenace

Reputation: 12836

Array dereferencing is only possible from php 5.5. If you have an earlier version, sadly, it will not be possible.

However you could try using list, which will assign all the array elements in pathinfo to individual variables. If you order your variables correctly, $file_name will have what you need.

Upvotes: 2

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