Reputation: 321
I have a list containing several vectors, e.g.:
ls=list(c("g1","g3","g6"),c("g1","g4"),c("g2","g5"),c("g2","g5"),c("g2"))
I want to capture the minimum number of elements so that I have at least one element from each vector.
So in this example, "g1" and "g2" because g1 captures vectors 1 and 2 and g2 captures vectors 1, 3, 4 and 5.
I've been looking at How to find common elements from multiple vectors? but it isn't quite the same question.
Upvotes: 1
Views: 456
Reputation: 132676
Brute force:
ls <- list(c("g1","g3","g6"),c("g1","g4"),c("g2","g5"),c("g2","g5"),c("g2"))
#unique values:
vals <- unique(do.call(c,ls))
#matrix indicating in which list each value is present
valsin <- sapply(ls,function(x) as.integer(vals %in% x))
rownames(valsin) <- vals
#loop through numbers of values to take for combinations
for (i in seq_along(vals)) {
cat(paste0(i,"\n"))
#Do combinations fullfill condition?
suff <- combn(seq_along(vals),i,FUN=function(x) {
identical(colSums(valsin[x,,drop=FALSE]),rep(1,length(ls)))
})
if (sum(suff) > 0) {
#combinations that fullfill condition
res <- combn(vals,i)[,suff]
#stop loop if condition has been fullfilled
break
}
}
res
#[1] "g1" "g2"
Upvotes: 1