CODEWITHSUNDEEP
pythonsorting
Tommy
Tommy

Reputation: 427

having trouble of sorting list in python

a=[(' ', '000'), ('\n', '001000'), ('v', '00100100'), ('O', '0010010100'),('e', '110'), ('n', '1110'), ('r', '1111')]

and i want to sort the list first by the length of the number and then for the alphabetical order of all character that have the same length of number. i have tried to sort by for loop but it just sorts my length of number and not for alphabetical order.

a=[(' ', '000'), ('\n', '001000'), ('v', '00100100'), ('O', '0010010100'),('e', '110'), ('n', '1110'), ('r', '1111')]
for i in range (len(a)):
    for j in range(1,len(a)):
        if len(a[i][1])>len(a[j][1]):
            swap = a[i]
            a[i]=a[j]
            a[j]=swap

does anyone have any idea ??? thanks in advance

Upvotes: 0

Views: 61

Answers (1)

Blender
Blender

Reputation: 298046

Use the key argument to sort:

a.sort(key=lambda item: (len(item[1]), item[0]))

Or more verbosely:

def sort_func(item):
    return len(item[1]), item[0]

a.sort(key=sort_func)

Upvotes: 4

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