CODEWITHSUNDEEP
php
jmenezes
jmenezes

Reputation: 1926

Check array for multiple keys

Is it possible to check in one go if multiple keys exists in an array, instead of using the array_key_exists function multiple times? Or, can this be achieved another way?

<?php
$search_array = array('first' => 1, 'second' => 4);

if(array_key_exists('first','second' $search_array))//Do something like this. 
{
    echo "The 'first' element is in the array";
}
?>

Upvotes: 3

Views: 3956

Answers (3)

underscore
underscore

Reputation: 6887

See https://web.archive.org/web/20130527004746/http://php.net/manual/en/function.array-key-exists.php.

One note says

this function very good to use if you need to verify many variables:

<?php
function array_key_exists_r($keys, $search_r) {
    $keys_r = split('\|',$keys);
    foreach($keys_r as $key)
    if(!array_key_exists($key,$search_r))
    return false;
    return true;
}
?>

e.g.

<?php
if(array_key_exists_r('login|user|passwd',$_GET)) {
// login
} else {
// other
}
?>

Upvotes: 5

Gauthier
Gauthier

Reputation: 1321

Not an out of the box function, The solution by Samitha Hewawasam has if fully commented.

if(array_key_exists_r('first|second',$search_array)) {
    // searching for items in array
} else {
    // other
}

This should help you out. It will search for your items seperated by pipes (|) I pull this from http://php.net/manual/en/function.array-key-exists.php

Upvotes: 2

bwoebi
bwoebi

Reputation: 23777

function keysInArray ($array, $keys) {
    foreach ($keys as $key)
        if (!array_key_exists($key, $array))
            return false; // failure, if any key doesn't exist
    return true; // else true; it hasn't failed yet
}

And call it with:

if (keysInArray($searchArray, array("key1", "key2", /*...*/))) { /* ... */ }

And yes, you have to use multiple checks (e.g. in a loop); there doesn't exist an all-in-one function.

Upvotes: 1

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