CODEWITHSUNDEEP
c++inheritance
Praveen Kumar
Praveen Kumar

Reputation: 55

why cant i access class A function in following code?

the error i get for obj.a::get(); is class a is inaccessible, i know that obj.get()would flag an error, but i guess this should work, whats the issue here?

class a {
    int arg1;
public:
    a(int i){
        arg1 = i;
        cout << "a() called" << endl;
    }

    void get() {
        cout << "arg1=" << arg1 << endl;
    }
};


class b {
    int arg2;
public:
    b(int j) {
        arg2 = j;
        cout << "b() called" << endl;
    }

    void get() {
        cout << "arg2=" << arg2 << endl;
    }
};

class c: private a, private b {
    int arg3;
public:
    c(int i, int j, int k): b(k), a(j) {
        arg3 = k;
        cout << "c() called" << endl;
    }
};

int main() {
    c obj(1, 2, 3);
    obj.a::get();
}

Upvotes: 1

Views: 100

Answers (1)

Andy Prowl
Andy Prowl

Reputation: 126432

c uses private to derive from a, so the a subobject of c is inaccessible from functions which are not member functions of c.

Upvotes: 10

Related Questions