Reputation: 2991
I'm currently working on a map editor for a game in pygame, using tile maps. The level is built up out of blocks in the following structure (though much larger):
level1 = (
(1,1,1,1,1,1)
(1,0,0,0,0,1)
(1,0,0,0,0,1)
(1,0,0,0,0,1)
(1,0,0,0,0,1)
(1,1,1,1,1,1))
where "1" is a block that's a wall and "0" is a block that's empty air.
The following code is basically the one handling the change of block type:
clicked = pygame.mouse.get_pressed()
if clicked[0] == 1:
currLevel[((mousey+cameraY)/60)][((mousex+cameraX)/60)] = 1
But since the level is stored in a tuple, I'm unable to change the values of the different blocks. How do I go about changing the different values in the level in an easy manner?
Upvotes: 299
Views: 919306
Reputation: 1927
In my case, I wanted to merge rows/ lists
:
a = ['Tom', 'Dick', 'Harry']
b = ['20', '32', '14']
c = ['foo', 'bar', 'blah']
lines = [list(row) for row in zip(a, b, c)]
lines = [['Tom', '20', 'foo'], ...]
Upvotes: 1
Reputation: 41
Just using the command list did not work for me.
if you have a tuple just iterate until you have the elements there are necessary and after that append to a list. And if you go to the element level you can change it easily.
input:
level1 = (
(1,1,1,1,1,1),
(1,0,0,0,0,1),
(1,0,0,0,0,1),
(1,0,0,0,0,1),
(1,0,0,0,0,1),
(1,1,1,1,1,1))
level1_as_list=[]
for i in level1:
inside_list=[]
for j in i:
inside_list.append(j)
level1_as_list.append(inside_list)
print(level1_as_list)enter code here
output:
[[1, 1, 1, 1, 1, 1], [1, 0, 0, 0, 0, 1], [1, 0, 0, 0, 0, 1], [1, 0, 0, 0, 0, 1], [1, 0, 0, 0, 0, 1], [1, 1, 1, 1, 1, 1]]
Upvotes: 2
Reputation: 9086
Since Python 3.5 (PEP 448 -- Additional Unpacking Generalizations) one can use the following literal syntax to convert a tuple to a list:
>>> t = (1,2,3)
>>> lst = [*t]
>>> lst
[1, 2, 3]
>>> *lst, # back to tuple
(1, 2, 3)
A list comprehension can be use to convert a tuple of tuples to a list of lists:
>>> level1 = (
... (1,1,1,1,1,1),
... (1,0,0,0,0,1),
... (1,0,0,0,0,1),
... (1,0,0,0,0,1),
... (1,0,0,0,0,1),
... (1,1,1,1,1,1))
>>> level1_list = [[*row] for row in level1]
>>> level1_list
[[1, 1, 1, 1, 1, 1],
[1, 0, 0, 0, 0, 1],
[1, 0, 0, 0, 0, 1],
[1, 0, 0, 0, 0, 1],
[1, 0, 0, 0, 0, 1],
[1, 1, 1, 1, 1, 1]]
>>> *((*row,) for row in level1_list),
((1, 1, 1, 1, 1, 1),
(1, 0, 0, 0, 0, 1),
(1, 0, 0, 0, 0, 1),
(1, 0, 0, 0, 0, 1),
(1, 0, 0, 0, 0, 1),
(1, 1, 1, 1, 1, 1))
>>> _ == level1
True
Upvotes: 29
Reputation: 61
List to Tuple and back can be done as below
import ast, sys
input_str = sys.stdin.read()
input_tuple = ast.literal_eval(input_str)
l = list(input_tuple)
l.append('Python')
#print(l)
tuple_2 = tuple(l)
# Make sure to name the final tuple 'tuple_2'
print(tuple_2)
Upvotes: 6
Reputation: 2777
To convert tuples to list
(Commas were missing between the tuples in the given question, it was added to prevent error message)
Method 1:
level1 = (
(1,1,1,1,1,1),
(1,0,0,0,0,1),
(1,0,0,0,0,1),
(1,0,0,0,0,1),
(1,0,0,0,0,1),
(1,1,1,1,1,1))
level1 = [list(row) for row in level1]
print(level1)
Method 2:
level1 = map(list,level1)
print(list(level1))
Method 1 took --- 0.0019991397857666016 seconds ---
Method 2 took --- 0.0010001659393310547 seconds ---
Upvotes: 20
Reputation: 309
Why don't you try converting its type from a tuple to a list and vice versa.
level1 = (
(1,1,1,1,1,1)
(1,0,0,0,0,1)
(1,0,0,0,0,1)
(1,0,0,0,0,1)
(1,0,0,0,0,1)
(1,1,1,1,1,1))
print(level1)
level1 = list(level1)
print(level1)
level1 = tuple(level1)
print(level1)
Upvotes: 16
Reputation: 19406
You have a tuple of tuples.
To convert every tuple to a list:
[list(i) for i in level] # list of lists
--- OR ---
map(list, level)
And after you are done editing, just convert them back:
tuple(tuple(i) for i in edited) # tuple of tuples
--- OR --- (Thanks @jamylak)
tuple(itertools.imap(tuple, edited))
You can also use a numpy array:
>>> a = numpy.array(level1)
>>> a
array([[1, 1, 1, 1, 1, 1],
[1, 0, 0, 0, 0, 1],
[1, 0, 0, 0, 0, 1],
[1, 0, 0, 0, 0, 1],
[1, 0, 0, 0, 0, 1],
[1, 1, 1, 1, 1, 1]])
For manipulating:
if clicked[0] == 1:
x = (mousey + cameraY) // 60 # For readability
y = (mousex + cameraX) // 60 # For readability
a[x][y] = 1
Upvotes: 90
Reputation: 4248
Convert tuple to list:
>>> t = ('my', 'name', 'is', 'mr', 'tuple')
>>> t
('my', 'name', 'is', 'mr', 'tuple')
>>> list(t)
['my', 'name', 'is', 'mr', 'tuple']
Convert list to tuple:
>>> l = ['my', 'name', 'is', 'mr', 'list']
>>> l
['my', 'name', 'is', 'mr', 'list']
>>> tuple(l)
('my', 'name', 'is', 'mr', 'list')
Upvotes: 388
Reputation: 1481
Both the answers are good, but a little advice:
Tuples are immutable, which implies that they cannot be changed. So if you need to manipulate data, it is better to store data in a list, it will reduce unnecessary overhead.
In your case extract the data to a list, as shown by eumiro, and after modifying create a similar tuple of similar structure as answer given by Schoolboy.
Also as suggested using numpy array is a better option
Upvotes: 5
Reputation: 59426
You could dramatically speed up your stuff if you used just one list instead of a list of lists. This is possible of course only if all your inner lists are of the same size (which is true in your example, so I just assume this).
WIDTH = 6
level1 = [ 1,1,1,1,1,1,
1,0,0,0,0,1,
1,0,0,0,0,1,
1,0,0,0,0,1,
1,0,0,0,0,1,
1,1,1,1,1,1 ]
print level1[x + y*WIDTH] # print value at (x,y)
And you could be even faster if you used a bitfield instead of a list:
WIDTH = 8 # better align your width to bytes, eases things later
level1 = 0xFC84848484FC # bit field representation of the level
print "1" if level1 & mask(x, y) else "0" # print bit at (x, y)
level1 |= mask(x, y) # set bit at (x, y)
level1 &= ~mask(x, y) # clear bit at (x, y)
with
def mask(x, y):
return 1 << (WIDTH-x + y*WIDTH)
But that's working only if your fields just contain 0 or 1 of course. If you need more values, you'd have to combine several bits which would make the issue much more complicated.
Upvotes: 3
Reputation: 212835
You can have a list of lists. Convert your tuple of tuples to a list of lists using:
level1 = [list(row) for row in level1]
or
level1 = map(list, level1)
and modify them accordingly.
But a numpy array is cooler.
Upvotes: 27