CODEWITHSUNDEEP
c++
ghostrider
ghostrider

Reputation: 5259

call inline function of another header file from a header file c++

I am having 2 header (.hh) files and there are some functions defined and implemented in both of these files:

What I want it so call a function of the other header file (let's call it B) from an implementation in header file A.

Here is what I have:

//headerA.hh
LSQUnit<Impl>::read(...args....)
   ...
callfunction(...args...);
}

where the implementation of call function is in the other header file like this:

// headerB.hh   
template<class Impl>
    inline void
    BaseDynInst<Impl>::callfunction (...args...){
       ....
    }

I have added in my headerA.hh these:

#include "headerB.hh"
....
void call function (...args...)

but I get undefined reference to callfunction in my headerA.hh

I have also tried these:

when I call it from headerA.hh

callfunction<BaseDynInst> callfunction (...args...)

or add this impleentation of this in my headerB.hh:

LSQUnit<Impl>::callfunction(...args...)

but they gave me more errors.

I know that putting implementations inside .hh may not be ideal but I am using a simulator which is not created by me, so I cannot change that because it will make things worse.

Is it possible what I want or the only solution is to implement the function inside headerA.hh ? I want to avoid that because it calls many others that all exist in headerB.hh?

Upvotes: 1

Views: 313

Answers (1)

stardust
stardust

Reputation: 5998

It seems callFunction is a non-static member function of a template class. the corect way to call it is

LSQUnit<Impl> something;
something.callFunction(...);

That means you need an object of the class type which owns callFunction. In this case something.

This syntax

LSQUnit<Impl>::callfunction(...args...)

is for calling static member functions.

Upvotes: 2

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