Reputation: 69
I have written a line that finds and returns the full path to a desired file. The output is as follows:
/home/ke/Desktop/b/o/r/files.txt:am.torrent
/home/ke/Desktop/y/u/n/u/s/files.txt:asd.torrent
I have to modify the output like this:
bor
yunus
How do I do that?
Thanks in advance.
Upvotes: 0
Views: 174
Reputation: 26164
This should work for you:
your_script.sh | sed 's,.*Desktop,,' | sed 's,[^/]*$,,' | sed s,/,,g
or, even better:
your_script.sh | sed 's,.*Desktop,,;s,[^/]*$,,;s,/,,g'
Upvotes: 1
Reputation: 2524
it's not a nice/tidy solution, but bash parameter expansion is a powerful tool. So could not resist providing an example
[]l="/home/ke/Desktop/b/o/r/files.txt:am.torrent"
[]m=${l##*Desktop/}
[]n=${m%%/files.txt*}
[]k=${n//\//}
[]echo $m
b/o/r/files.txt:am.torrent
[]echo $n
b/o/r
[]echo $k
bor
You can see how nicely bash is replacing the variable step by step without using any external program (btw []
is PS1, prompt)
There can be many more ways to do it. I got another one while writing the first
[]l="/home/ke/Desktop/b/o/r/files.txt:am.torrent"
[]m=${l/*Desktop\//}
[]n=${m/\/files.txt*/}
[]k=${n//\//}
[]echo $m
b/o/r/files.txt:am.torrent
[]echo $n
b/o/r
[]echo $k
bor
Try some more,
Upvotes: 0
Reputation: 45634
Id resort to awk:
BEGIN { FS="/" }
{
for(i=1;i<NF;i++)
if (length($i) == 1)
a[NR]=a[NR]""$i
}
END {
for (i in a)
print a[i]
}
use it like this:
$ awk -f script.awk input
bor
yunus
or if you have your data in a variable:
$ awk -f script.awk <<< $data
Upvotes: 0
Reputation: 5029
With sed. echo '/home/ke/Desktop/b/o/r/files.txt:am.torrent' | sed -e 's+/++g' -e 's/^.*Desktop//' -e 's/files.txt:.*$//'
. This is a fairly trivial solution, and I'm sure there are better ones.
Upvotes: 0