CODEWITHSUNDEEP
phpregex
jlafforgue
jlafforgue

Reputation: 287

PHP replace image content

I'm not an expert with Regex, but I'm trying to convert an image URL to another and delete the height and width attributes...

$content = preg_replace('/src="([^"]*)(png|jpeg|jpg|gif|bmp)"/', 'src="http://www.mysite.com/thumb.php?url=$1&width=500&height=500"', $post_content);

$content = preg_replace( '/(width|height)=\"\d*\"\s/', "", $content);

echo $content;

Echoing the results doesn't give me an image extension:

<img src="http://www.mysite.com/thumb.php?url=http://www.mysite.com/wp-content/uploads/2013/02/image.&width=500&height=500" />

How can I do this?

Upvotes: 0

Views: 192

Answers (1)

Alex Shesterov
Alex Shesterov

Reputation: 27525

The $1 in your replacement-string refers to the first capturing group of your regex. In other words, the value of $1 is the character sequence matched by the first (...) in the regex.

The problem is, your first set of parentheses does not include file extensions - hence the missing filename extension in the result.

Upvotes: 2

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