CODEWITHSUNDEEP
pythonpython-2.7
user266003
user266003

Reputation:

Print prints some extra signs

I create a method to print some stuff:

def my_print(*str1):
  print '---------------'
  print str1
  print '---------------'


my_print('1fdsfd %s -- %s' % (12, 18))

which gives me

---------------
('1fdsfd 12 -- 18',)
---------------

Why do I have these extra ( and ) and even , and how do I get rid of them?

Upvotes: 1

Views: 54

Answers (3)

Ashwini Chaudhary
Ashwini Chaudhary

Reputation: 251051

The reason is due to * the str1 is converted into a tuple inside the my_print function, you can either remove the * or use print str1[0].

When a * is used in functions definition then it behave as a collector, and collects all the positional arguments passed to function in a tuple.

>>> def func(*a):
...     print type(a)
...     print a
...     
>>> func(1)
<type 'tuple'>
(1,)
>>> func(1,2,3)
<type 'tuple'>
(1, 2, 3)

Working version of your code:

def my_print(str1):
  print '---------------'
  print str1
  print '---------------'


my_print('1fdsfd %s -- %s' % (12, 18))

or :

def my_print(*str1):
  print '---------------'
  print str1[0]
  print '---------------'


my_print('1fdsfd %s -- %s' % (12, 18))

Upvotes: 2

jamylak
jamylak

Reputation: 133624

Since you are unpacking all the arguments given to your function with the splat (*) operator, you are getting a tuple of arguments saved to str1 eg.

>>> my_print('a', 'b')
---------------
('a', 'b')
---------------

Then you are simply printing the tuple of arguments, it seems like you don't need the splat since you only have str1 so just remove it and it works fine.

Upvotes: 0

TerryA
TerryA

Reputation: 60004

Remove the * and use str.format() instead:

mytuple = (12, 18)
my_print('1fdsfd {0} -- {1}'.format(*mytuple)) # I've used the * here to unpack the tuple.

As others have pointed out, it converts str1 into a tuple.

Upvotes: 0

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