CODEWITHSUNDEEP
pythonmaya
Vii
Vii

Reputation: 841

Python Maya - If objectType returns "No object name specified"

I am trying to get maya to check if the listed object is a blendshape node or not.

This is my code:

def bake(self, *args):
    self.items["selection"] = cmds.ls(sl = True)
    self.items["shapes"] = cmds.listRelatives(self.items["selection"], ad = True)
    shapes = ()
    for i in self.items["shapes"]:
        bs = cmds.listConnections(i, type = "blendShape", exactType = True)
        if cmds.objectType(bs, isType = "blendShape"):
            print bs

It returns # Error: RuntimeError: file X:/Documents/maya/scripts\jtBakeCharacter.py line 16: No object name specified

Line 16 is: if cmds.objectType(bs, isType = "blendShape"):

Except that I AM specifying an object name, that object name is bs .. I have printed the result of bs and it has many objects listed. Many.

Upvotes: 1

Views: 2442

Answers (3)

theodox
theodox

Reputation: 12208

Joojaa's answer is elegant, but you can get it down even shorter by using the default selection behavior:

blendshapes = cmds.ls(cmds.listHistory(pdo=True), type='blendShape') or []
for item in blendshapes:
    print item

(In the quest to make it even shorter I'm not checking for the selection, so this one fails if nothing is selected).

PS: if you need to get to the blendshape from one of the upstream shapes, instead of the deformed shape, you can use listHistory (f=True)

Upvotes: 1

joojaa
joojaa

Reputation: 4434

The code is redundant. You don't need most of the lines. The listConnections already ensures that you have only blendshapes. The exact problem is that you are calling something like:

cmds.objectType([])

for some of those extra shapes. And this is illegal. But mostly you code can be encapsulated as follows:

selected = cmds.ls(sl = True, dag=True ,shapes = True)
blends = cmds.listConnections(selected , type = "blendShape", exactType = True)
for item in blends:
    print item

But this may not catch your intent perfectly, but shows how may extra steps you take. In reality you don't need the line if cmds.objectType(bs, isType = "blendShape"): for anything

Upvotes: 3

Argiri Kotsaris
Argiri Kotsaris

Reputation: 492

You could try this:

from pymel.core import *

for obj in selected():
    shapeNode = obj.getChildren()[0]
    for output in shapeNode.outputs():
        if nodeType(output) == "blendShape":
            print obj, "is a blendshape"

Upvotes: 0

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