Reputation: 22234
Here's my code as is, working, but very slow:
$graded = R::getAll("SELECT posts.id, posts.discussion, rating.rating, rating.itemid
FROM uv_forum_posts posts
JOIN uv_rating rating ON ( posts.id = rating.itemid )
WHERE posts.discussion = :discussion_id
GROUP BY posts.userid",
array(':discussion_id' => $discussion['id']));
$total = R::getAll("SELECT posts.userid
FROM uv_forum_posts posts
WHERE posts.discussion = :discussion_id
GROUP BY userid",
array(':discussion_id' => $discussion['id']));
$percentages[] = count($graded) / count($total) * 100;
$graded
represents all rows that have a rating.
$total
represents all user participation, regardless of being graded or not.
I'm only interested in the numerical values of the resulting sets, can I combine these two MySQL calls into a single call that returns two numbers graded
and total
?
Upvotes: 0
Views: 131
Reputation: 92785
If I correctly understand your requirements you can try
SELECT p.userid,
COUNT(*) total,
COUNT(r.itemid) graded
FROM uv_forum_posts p LEFT JOIN
uv_rating r ON p.id = r.itemid
WHERE p.discussion = :discussion_id
GROUP BY p.userid
Output:
| USERID | TOTAL | GRADED |
---------------------------
| 1 | 8 | 2 |
| 2 | 4 | 4 |
UPDATE: If you just want grand total for all posts and users then
SELECT COUNT(*) total,
COUNT(r.itemid) graded
FROM uv_forum_posts p LEFT JOIN
uv_rating r ON p.id = r.itemid
WHERE p.discussion = 1
Output:
| TOTAL | GRADED |
------------------
| 12 | 6 |
Upvotes: 1
Reputation: 1225
You could simply use a query as in the format :
Select
( SELECT posts.id, posts.discussion, rating.rating, rating.itemid
FROM uv_forum_posts posts
JOIN uv_rating rating ON ( posts.id = rating.itemid )
WHERE posts.discussion = :discussion_id
GROUP BY posts.userid,
array(':discussion_id' => $discussion['id']))) gradeCount,
(SELECT posts.userid
FROM uv_forum_posts posts
WHERE posts.discussion = :discussion_id
GROUP BY userid,
array(':discussion_id' => $discussion['id'])))totalCount
Upvotes: 0