CODEWITHSUNDEEP
pythondatetimefeedparser
Jacob Irwin
Jacob Irwin

Reputation: 153

Parsing out all timestamps in RSS feed using feedparser

I am fairly new to the feedparser lib in Python.

Trying to parse out a complete list of timestamps from a RSS feed, I currently have:

import feedparser
from time import gmtime, strftime

d = feedparser.parse('http://www.bloomberg.com/feed/podcast/taking-stock.xml')
dPub = d.entries[0].published   # out: u'Mon, 06 May 2013 08:19:36 -0400'
dPubPretty = strftime(dPub, gmtime())
print dPubPretty    # out: Mon, 06 May 2013 08:19:36 -0400

# loop over d.entries[0:] - ???
# for all d.entries...

d.entries[1].published  # out: u'Mon, 06 May 2013 08:16:15 -0400'
d.entries[2].published  # out: u'Fri, 03 May 2013 09:01:50 -0400'

I'd like to loop over all d.entries and output a list of timestamps, so with strftime() applied, the output would be something like:

# output goal:
Mon, 06 May 2013 08:19:36 -0400
Mon, 06 May 2013 08:16:15 -0400
Fri, 03 May 2013 09:01:50 -0400
...

Referencing these docs:

feedparser - Content Normalization: http://pythonhosted.org/feedparser/content-normalization.html#advanced-normalization

time - Time access and conversions: http://docs.python.org/2/library/time.html#time.strftime

Upvotes: 2

Views: 2203

Answers (1)

jabaldonedo
jabaldonedo

Reputation: 26572

Try to iterate over each entry

import feedparser
from time import gmtime, strftime

d = feedparser.parse('http://www.bloomberg.com/feed/podcast/taking-stock.xml')

for entry in d.entries:
    dPub = entry.published  
    dPubPretty = strftime(dPub, gmtime())
    print dPubPretty

You will get the following output:

Mon, 06 May 2013 08:19:36 -0400
Mon, 06 May 2013 08:16:15 -0400
Fri, 03 May 2013 09:01:50 -0400
Fri, 03 May 2013 08:57:55 -0400
Fri, 03 May 2013 08:54:21 -0400
Thu, 02 May 2013 10:04:42 -0400
Thu, 02 May 2013 09:38:42 -0400
...
Mon, 18 Mar 2013 08:03:27 -0400
Mon, 18 Mar 2013 08:01:21 -0400

Upvotes: 2

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