Reputation: 1620
I need to Upload Image selected in the Website into the DB My project has multiple File Select "File Upload" how can I Upload those multiple Files into Database the Image data in Binary Format, My Code is
protected void Button1_Click(object sender, EventArgs e)
{
string Qry = "insert into tblFiles values(@data)";
SqlConnection con = new SqlConnection(@"Data Source=ESLHPC17\SQL2008;Initial Catalog=dbFiles;User ID=user;Password=password");
SqlCommand cmd = new SqlCommand(Qry,con);
cmd.Parameters.Add("@data") = FileUpload1.FileBytes;
}
I am using the Following Web Handler to Save the Files in local Folder
<%@ WebHandler Language="C#" Class="Upload" %>
using System;
using System.Web;
using System.IO;
public class Upload : IHttpHandler {
public void ProcessRequest (HttpContext context) {
context.Response.ContentType = "text/plain";
context.Response.Expires = -1;
try
{
HttpPostedFile postedFile = context.Request.Files["Filedata"];
string savepath = "";
string tempPath = "";
tempPath = System.Configuration.ConfigurationManager.AppSettings["FolderPath"];
savepath = context.Server.MapPath(tempPath);
string filename = postedFile.FileName;
if (!Directory.Exists(savepath))
Directory.CreateDirectory(savepath);
postedFile.SaveAs(savepath + @"\" + filename);
context.Response.Write(tempPath + "/" + filename);
context.Response.StatusCode = 200;
}
catch (Exception ex)
{
context.Response.Write("Error: " + ex.Message);
}
}
public bool IsReusable {
get {
return false;
}
}
}
and I use the below Script
<script type = "text/javascript">
$(window).load(
function () {
$("#<%=FileUpload1.ClientID%>").fileUpload({
'uploader': 'scripts/uploader.swf',
'cancelImg': 'images/cancel.png',
'buttonText': 'Browse Files',
'script': 'Upload.ashx',
'folder': 'Uploads',
'fileDesc': 'Image Files',
'fileExt': '*.jpg;*.jpeg;*.gif;*.png',
'multi': true,
'auto': false
});
but I want to store the Images in Database
@ Damith
I have tried in with the below mentioned code but it didn't worked,
protected void Button1_Click(object sender, EventArgs e)
{
string FolderPath=@"E:\Rajesh_Kumar\Application\Valuation\ExamManagement\ExamManagement\Uploads";
string path = System.Configuration.ConfigurationManager.AppSettings[FolderPath];
string Qry = "insert into tblFiles values(@data) Values (data)";
SqlConnection con = new SqlConnection(@"Data Source=ESLHPC17\SQL2008;Initial Catalog=dbFiles;User ID=rajesh";
StreamReader sr = new StreamReader(path);
while (sr.ReadLine() != null)
{
using (SqlCommand cmd = new SqlCommand(Qry, con))
{
cmd.Parameters.Add("@data",SqlDbType.VarBinary).Value = path;
con.Open();
cmd.ExecuteNonQuery();
}
con.Close();
con.Dispose();
}
}
Upvotes: 0
Views: 1552
Reputation: 63065
try with
foreach (HttpPostedFile uploadedFile in FileUpload1.PostedFiles)
{
SaveImage(uploadedFile);
}
private void SaveImage(HttpPostedFile file)
{
using(SqlConnection con = new SqlConnection(ConnectionString))// set ConnectionString
{
using(SqlCommand cmd = new SqlCommand(Qry,con)) // set Qry
{
cmd.Parameters.AddWithValue("@data", ReadFile(file));
con.Open();
cmd.ExecuteNonQuery();
}
}
}
private byte[] ReadFile(HttpPostedFile file)
{
byte[] data = new Byte[file.ContentLength];
file.InputStream.Read(data, 0, file.ContentLength);
return data;
}
If you need to insert images from server folder and assume you have array of image paths as imageArray
then
foreach (var path in imageArray)
{
SaveImage(path);
}
private void SaveImage(string path)
{
using(SqlConnection con = new SqlConnection(ConnectionString))// set ConnectionString
{
using(SqlCommand cmd = new SqlCommand(Qry,con)) // set Qry
{
cmd.Parameters.AddWithValue("@data", System.IO.File.ReadAllBytes(path));
con.Open();
cmd.ExecuteNonQuery();
}
}
}
Upvotes: 2
Reputation: 6434
foreach(HttpPostedFile file in FileUpload1.PostedFiles)
{
var memoryStream = new MemoryStream();
file.InputStream.CopyTo(memoryStream);
string Qry = "insert into tblFiles values(@data)";
SqlConnection con = new SqlConnection(@"Data Source=ESLHPC17\SQL2008;Initial Catalog=dbFiles;User ID=user;Password=password");
SqlCommand cmd = new SqlCommand(Qry,con);
cmd.Parameters.Add("@data") = memoryStream.ToArray();
}
Upvotes: 1