CODEWITHSUNDEEP
phphtmlajax
Tom
Tom

Reputation:

Load a section of page separately from the rest?

I want to check the status of a couple of servers and display on a page if they're up or down. Currently, I'm doing this with PHP's fsockopen() function. As part of this function, you determine a timeout time. This means that if the servers are down, it'll block for say 2 seconds before moving on. This causes my webpage to wait till the fsockopen()s are done before it displays the page.

Is there a way to get these fsockopen() functions to run separately from the rendering of the page, and have their results included in after they're determined? It doesn't have to be PHP, I guess.

Upvotes: 1

Views: 268

Answers (3)

Hugo Delsing
Hugo Delsing

Reputation: 14173

Create a php page that accepts a variable to know which server to check

<?php
$server = isset($_GET['server']) ? $_GET['server'] : '';
$upordown = 'invalid server'; //default incase wrong variable is set

switch ($server) {
  case 'server1':
    //check server 1; EG: $upordown = checkserver('http://www.example.com');
    break;
  case 'server2':
    //check server 2;
    break;
  case 'server3':
    //check server 3;
    break;
}

echo $upordown
?>

and then on your show page using jquery:

<html>
<head>
  <script src='jquery.js'></script>
  <script>
  $(function(){
    $('.serverstatus').each(function() {
      var id = $(this).data('serverid');
      $(this).load('/servercheck.php?server='+id);
    });
  });
  </script>
</head>
<body>
  <div class='serverstatus' data-serverid='server1'>loading</div>
  <div class='serverstatus' data-serverid='server2'>loading</div>
  <div class='serverstatus' data-serverid='server3'>loading</div>
</body>
</html>

Now you could add some extra safety like caching and random servernames instead of 1,2,3

Upvotes: 0

Jonathon
Jonathon

Reputation: 16333

Use AJAX. I'd recommend using jQuery's $.ajax function (http://api.jquery.com/jQuery.ajax/) to call a PHP script which will query a server. You will provide a success function to the ajax call which will be executed when the ajax call has finished.

Upvotes: 0

Tasos Bitsios
Tasos Bitsios

Reputation: 2799

Split this into two sub-problems:

1) Create a cron job (or otherwise schedule) a script that will check the server status and save that result somewhere (db, cache, file, post-it, etc). Run it as frequently as you like.

2) Query that result either while rendering the page or via an AJAX call.

Upvotes: 1

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