CODEWITHSUNDEEP
c++unixtime
knight666
knight666

Reputation: 1619

Converting a unix time to a human readable format

I'm building my own unix time to human readable conversion, and I'm stuck.

I can extract the year just fine, but the day is proving too tricky.

/*
   Converts a 32-bit number of seconds after 01-01-1970 to a _SYSTEMTIME structure
*/
static _SYSTEMTIME Convert(unsigned long a_UnixTime)
{   
    newtime.wMilliseconds = 0;
    newtime.wYear   = (unsigned long)((float)a_UnixTime / (364.24f * 24.f * 60.f * 60.f));
    newtime.wDay    = (a_UnixTime - (unsigned long)((float)newtime.wYear * 364.24f * 24.f * 60.f * 60.f)); // returns 65177

    return newtime;
}

Or is there a built-in function that I've overlooked?

Thanks in advance.

UPDATE:

Hmm... it seems Windows Mobile doesn't support strftime, time or localtime, so I'll still have to roll my own. :(

Upvotes: 0

Views: 3157

Answers (2)

unwind
unwind

Reputation: 399833

If you want to format to print, you need strftime(), it's the standard solution, used together with e.g. localtime() to convert the raw timestamp to a more human-friendly format.

Upvotes: 1

diciu
diciu

Reputation: 29333

Are you looking for gmtime?

struct tm * gmtime(const time_t *clock);

External declarations, as well as the tm structure definition, are contained in the <time.h> include file.  The tm structure includes at least the following fields:

       int tm_sec;     /* seconds (0 - 60) */
       int tm_min;     /* minutes (0 - 59) */
       int tm_hour;    /* hours (0 - 23) */
       int tm_mday;    /* day of month (1 - 31) */
       int tm_mon;     /* month of year (0 - 11) */
       int tm_year;    /* year - 1900 */
       int tm_wday;    /* day of week (Sunday = 0) */
       int tm_yday;    /* day of year (0 - 365) */
       int tm_isdst;   /* is summer time in effect? */
       char *tm_zone;  /* abbreviation of timezone name */
       long tm_gmtoff; /* offset from UTC in seconds */

Upvotes: 2

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