user199049
user199049

Reputation:

JQuery Issue in IE7

I'm new to JQuery... this code doesn't work in IE7 but does in FF & Chrome. It says its giving me a syntax error, help!

$(function(){ $("#bClose").click(function() { $("#ContactRepeat").slideUp("normal"); });

$("#bContact").click(function() {
    if ($("#ContactRepeat").css("display") == "display"){
        $("#ContactRepeat").slideToggle("normal", function(){
            $("#ContactRepeat").slideToggle("normal");
        });
    }
    else {
        $("#ContactRepeat").slideToggle("normal");
    }
return false;
});

});

I'm using jQuery 1.2.6. Thank you for your help ahead of time

Upvotes: 1

Views: 352

Answers (1)

Paul Irish
Paul Irish

Reputation: 49242

The major flaw in your code is this line, btw:

$("#ContactRepeat").css("display") == "display" 

It'll never be display. Maybe none or block. But it's better to do .is(':visible') or .is(':hidden')

Here's a revised snippet. I'm not seeing any syntax errors being reported when i run this through JSLint

$(function(){ 
    var crepeat = $("#ContactRepeat");

    $("#bClose").click(function() { $( crepeat .slideUp("normal"); });

    $("#bContact").click(function() {

        if (crepeat.is(':visible')){
                $crepeat.slideToggle("normal", function(){
                        $(this).slideToggle("normal");
                });
        }
        else {
                crepeat.slideToggle("normal");
        }
        return false;
    });

});

Upvotes: 1

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