CODEWITHSUNDEEP
c#linq
priyanka.sarkar
priyanka.sarkar

Reputation: 26518

How to check if all the elements in an array are positive integers?

I have an array, say 

int[] array = new int[] { 1, 5, 11, 5 };

How can I check (in the most easy and efficient way) that all elements are positive? If at least one number is not a positive integer, the system will respond in a negative way.

Desired output:

if all the numbers are positive, then it will display "All Positive" else "Wrong"

My shot

int[] array = new int[] { 1, 5, 11, 5 };
var x = array.All(c => c >= '0' && c <= '9');
if (x == true) "Positive" else "Wrong";

Upvotes: 8

Views: 22605

Answers (5)

Habib
Habib

Reputation: 223282

Use Enumerable.Any like:

if(array.Any(r => r < 0))
{
     //Negative number found
}
else
{
   //All numbers are positive
}

Or you can use Enumerable.All Like:

if(array.All(r => r > 0))
{
    //All numbers are positive 
}
else
{
   //Negative number found
}

Upvotes: 6

G. Stoynev
G. Stoynev

Reputation: 7791

string result = array.Any(x => x < 0)?"Wrong":"Positive";

Upvotes: 1

Jon Skeet
Jon Skeet

Reputation: 1501926

You were nearly there before - but you were comparing with characters instead of integers.

If you want to check whether everything is strictly positive, use:

bool allPositive = array.All(x => x > 0);

If you actually want to check they're all non-negative (i.e. 0 is acceptable) use:

bool allNonNegative = array.All(x => x >= 0);

You should definitely consider what you want to do with 0, as your problem statement is actually contradictory. ("All positive" and "no negative" aren't the same thing.)

Note that just like Any, All will quit as soon as it knows the result - so if the first value is negative, it won't need to look through the rest.

Upvotes: 17

Soner G&#246;n&#252;l
Soner G&#246;n&#252;l

Reputation: 98810

You almost there. But in your condition, you comparing characters instead of integers which is wrong in your situation.

Use Enumerable.All like;

Determines whether all elements of a sequence satisfy a condition.

int[] array = new int[] { 1, 5, 11, 5 };
bool allPositive = array.All(x => x > 0);
Console.WriteLine(allPositive);

Here is a DEMO.

Remember 0 is not positive.

Upvotes: 3

Alexander Bell
Alexander Bell

Reputation: 7918

Below is a C# solution to your problem (it should be rather efficient performance-wise):

int[] array = new int[] { 1, 5, 11,5 };

bool _allPositive=true;

for (int i=0;i<array.length;i++){
 if(array[i]<0 {_allPositive=false; break;}
}

bool _allPositive indicates the result (you can use string var if you prefer). Essentially, the same syntax can apply to Java-like languages, including scripting.

Upvotes: 1

Related Questions