CODEWITHSUNDEEP
node.jsmongodbfind
Lars Natus
Lars Natus

Reputation: 333

Find query for MongoDB in node.js

I have the following query where the oids is an array of object id's. 

users.find({ _id: { $in: oids } }, function(err, result){
    console.log(result);
});

I expect a list of users where the id from the users are in the array of object id's, but the actual result looks like this:

{ db: { databaseName: 'users', serverConfig: { _callBackStore: [Object], host: 'localhost', port: 27017, options: [Object], internalMaster: true, connected: true, poolSize: 5, disableDriverBSONSizeCheck: false, slaveOk: undefined, _used: true, replicasetInstance: null, ssl: false, sslValidate: false, sslCA: null, sslCert: undefined, sslKey: undefined, sslPass: undefined, _readPreference: null, socketOptions: [Object], logger: [Object], eventHandlers: [Object], _serverState: 'connected', _state: [Object], recordQueryStats: false, db: [Circular], dbInstances: [Object], connectionPool: [Object], isMasterDoc: [Object] }, options: { w: 1 }, _applicationClosed: false, native_parser: undefined, bsonLib: { Code: [Function: Code], Symbol: [Function: Symbol], BSON: [Object], DBRef: [Function: DBRef], Binary: [Object], ObjectID: [Object], Long: [Object], Timestamp: [Object], Double: [Function: Double], MinKey: [Function: MinKey], MaxKey: [Function: MaxKey] }, bson: {} ... and so on ...

If I use user.findOne(...) the result is the expected user, but I like to query all users in the array.

Upvotes: 2

Views: 1261

Answers (1)

Abhishek Kumar
Abhishek Kumar

Reputation: 3366

find() method returns you a cursor, so 'result' is printing all the cursor details. I guess you have to do something like:

collection.find().toArray(function(err, results) {
     test.assertEquals(1, results.length);
});

Upvotes: 1

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