CODEWITHSUNDEEP
regex
user7282
user7282

Reputation: 5196

Regular expression find matched between a string and a space

I need to find out all words in a sentence that are between a $ and a space like this this is $abc $cde any $ety.

The result should be abc, cde and ety.

I tried this 

'(?<=$$)(.*)(?=)'

but it shows some error. What is wrong in this or any new suggestions?

Upvotes: 0

Views: 63

Answers (3)

pcalcao
pcalcao

Reputation: 15975

You can try this:

\$(\w+)

As capturing groups, you'll get each of the words.

\w will match a-Z, 0-9 and _, if you want to match only letters, for instance, you can change to: \$([a-zA-Z]+)

Upvotes: 1

Bill
Bill

Reputation: 5764

Assuming from the question, each word (word contains only chars A-Za-z) must begin with $ and have a space at the end. The following regex will match such words -- \$([A-Za-z])+ (there is a space at the end, which is hard to see due to the formatting here). If there are multiple spaces, you can use + (space before +, hard to see again due to formatting) at the end of the regex.

Then you can extract the first matching group (i.e. $1) as your matching word, and you need to do this in a loop till there are no more matches you can extract. That is something like -- 

while ($x =~ /\$([A-Za-z])+  /g) {
   // $1 is your match
}

If your word contains more than just chars, then you can use \w as mentioned by pcalcao, which will include both 0-9 and _

Upvotes: 0

filipko
filipko

Reputation: 965

Try this RegEx:

(?<=\$)([^\s]*)(?=\s)

Upvotes: 0

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