Reputation: 13
I am trying to upload file but i am not doing it through html form. QueryParam and PathParam can't be used. So can anyone tell how to pass stream.
My HttPClient looks like:
try
{
HttpClient httpclient = new DefaultHttpClient();
InputStream stream=new FileInputStream(new File("C:/localstore/ankita/Desert.jpg"));
String url="http://localhost:8080/Cloud/webresources/fileupload";
HttpPost httppost = new HttpPost(url);
HttpResponse response = httpclient.execute(httppost);
}
catch(Exception e){}
and my web service class looks somewhat like:
@Path("/fileupload")
public class UploadFileService {
@POST
@Consumes(MediaType.APPLICATION_OCTET_STREAM)
public Response uploadFile(InputStream in) throws IOException
{
String uploadedFileLocation = "c://filestore/Desert.jpg" ;
// save it
saveToFile(in, uploadedFileLocation);
String output = "File uploaded via Jersey based RESTFul Webservice to: " + uploadedFileLocation;
return Response.status(200).entity(output).build();
}
// save uploaded file to new location
private void saveToFile(InputStream uploadedInputStream,String uploadedFileLocation)
{
try {
OutputStream out = null;
int read = 0;
byte[] bytes = new byte[1024];
out = new FileOutputStream(new File(uploadedFileLocation));
while ((read = uploadedInputStream.read(bytes)) != -1)
{
out.write(bytes, 0, read);
}
out.flush();
out.close();
} catch (IOException e)
{
e.printStackTrace();
}
}
}
Can anyone help??
String url="http://localhost:8080/Cloud/webresources/fileupload";
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
InputStreamEntity reqEntity = new InputStreamEntity(new FileInputStream(new File("C:/localstore/ankita/Desert.jpg")), -1);
reqEntity.setContentType("binary/octet-stream");
reqEntity.setChunked(true); // Send in multiple parts if needed
httppost.setEntity(reqEntity);
HttpResponse response = httpclient.execute(httppost);
How web service will look like?
Upvotes: 0
Views: 7221
Reputation: 718738
You can't do it that way. You can't pass a stream in an HTTP request, because streams are not serializable.
The way to do this is to is create an HttpEntity
to wrap the stream (e.g. an InputStreamEntity
) then attach it to the HttpPOST
object using setEntity
. Then the POST is sent, the client will read from your stream and send the bytes as the request's "POST data".
Upvotes: 1