Reputation: 1044
I have next 2 tables:
table querys and table time:
id | text id | mid | country
1 hello 1 1 UK
2 hi 2 1 PL
3 sd 3 2 USA
id = mid, countries are different (UK, USA and so on).
I need to make next list:
UK - text 30 rows (this text has most mid in table 2 for UK)
USA - text 25 rows
PL - text 10 rows
...
SS - text 1 rows.
For now i have next idea: Get which MID for each country has max rows and get text by mid=id and sort it.
SELECT time.country,querys.text,COUNT(mid) AS cnt
FROM time INNER JOIN `querys` ON(time.mid = querys.id)
GROUP BY mid
ORDER BY country,cnt
DESC
But with this code i recieve all text with count of it. Such as
UK text1 30,
UK text2 25,
PL text2 10,
PL text3 5 ..
But i need only one max for each country, could anyone help how to cut the query to 1 max text for each country?
Upvotes: 3
Views: 940
Reputation: 263723
SELECT a.country,
b.text,
COUNT(*) AS cnt
FROM time a
INNER JOIN querys b
ON a.mid = b.id
INNER JOIN
(
SELECT Country,
MAX(totalCount) max_count
FROM
(
SELECT Country, Mid,
COUNT(*) totalCount
FROM time
GROUP BY Country, Mid
) s
GROUP BY Country
) c ON a.country = c.country
GROUP BY a.country, b.text, c.max_count
HAVING COUNT(*) = c.max_count
ORDER BY cnt DESC
OUTPUT
╔═════════╦══════╦═════╗
║ COUNTRY ║ TEXT ║ CNT ║
╠═════════╬══════╬═════╣
║ UA ║ sdf ║ 10 ║
║ USA ║ qw ║ 2 ║
╚═════════╩══════╩═════╝
Upvotes: 2