CODEWITHSUNDEEP
matlaboctavecell-array
Rafi Kamal
Rafi Kamal

Reputation: 4600

Octave appending in a 2D cell array

I'm trying to append an element at the end of a 2D cell array row. My code is:

b = cell(5, 0)
b(1) = {b(1, :), 2}   % Trying to append at the end of the first row

This gives me the error: error: A(I) = X: X must have the same size as I

I've also tried various other forms, such as: 

b = cell(5, 0)
b(1, end+1) = 2   % Ok, inserts 2 at [1,1]
b(2, end+1) = 3   % No, inserts 3 at [2,2] instead of [2, 1]

Upvotes: 2

Views: 13156

Answers (2)

Eitan T
Eitan T

Reputation: 32930

It seems that you are confused with cell array indexing.

If you want to append elements at the end of a row in a matrix (in your case, a cell array), you must still make sure that all rows are of the same size after the assignment, otherwise you'll trigger an error about mismatching dimensions.

Instead of b(1) = {b(1, :), 2}, the following should work:

b(1, end + 1) = 2

Alternatively, if you want to append an entire column array of cells to b, use horizontal concatenation, for example:

b = [b, {2; 3; 4; 5; 6}];

This should append a single cell at the end of each row of b.

Upvotes: 6

Roney Michael
Roney Michael

Reputation: 3994

The reason the element gets inserted at [2, 2] and not [1, 1] is that by the time you try to insert the second element, the value denoted by end has increased from 0 to 1.

The following should do what you need:

>> b = cell(5, 0)

b = 

Empty cell array: 5-by-0

>> b(1,1) = {2}

b = 

    [2]
    []
    []
    []
    []

>> b(2,1) = {3}

b = 

    [2]
    [3]
    []
    []
    []

>>

Upvotes: 2

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