Reputation: 2901

C# Regex.Match curly brackets- contents only? (exclude braces)

I've been unable to find an answer on this: can I use the Regex.Matches method to return only the contents of items with curly braces?

If I use the Regex ({[^}]*}) my MatchCollection values includes the braces. I want to match, but then only return the contents. Here's what I have so far:

Regex regex = new Regex(({[^}]*}), RegexOptions.IgnoreCase);
MatchCollection matches = regex.Matches("Test {Token1} {Token 2}");
// Results include braces (undesirable)
var results = matches.Cast<Match>().Select(m => m.Value).Distinct().ToList();

Upvotes: 22

Answers (8)

SteveL

Reputation: 101

Thanks all for the regex tips! I know that this is not the answer to the original question but in case it helps someone else, I created this string extension method based on all your recommendations so I can replace localized string constants.

/// <summary>
/// Replace all the text in curly brackets with the parameters by
/// order it apears in the text.
/// </summary>
/// <remarks>This is to be use with const string that cannot be 
/// interpolated with $ or String.Format.</remarks>
/// <param name="text">The text that contains string in curly 
/// brackets.</param>
/// <param name="replaceTexts">The list of replace texts ordered as 
/// it apear in the <paramref name="text"/></param>
/// <returns>The interpolated text where string in curly brackets 
/// are replaced with the replaceTexts parameters.</returns>
public static string ReplaceText(this string text, params string[] replaceTexts)
{
    if (string.IsNullOrEmpty(text)) return text;
    
    // Found all {TextToReplace} and results includes curlybraket 
    // so we can use string.Replace
    var matches = Regex.Matches(text, @"{(.*?)}");            
    var results = matches.Cast<Match>()
                         .Select(m => m.Value).Distinct().ToList();
    
    // Nothing to replace in the text, just return it
    if(!results.Any()) return text;
    
    // The number of element to replace must match 
    // the replaceTexts parameter
    if(results.Count() != replaceTexts.Count())
    {
        throw new ArgumentOutOfRangeException(nameof(replaceTexts), "The text must conaints the exact same number of curly brackets string to replace than the replaceTexts parameters.");
    }

    var index = 0;
    foreach (var result in results)
    {
        text = text.Replace(result, replaceTexts[index++]);
    }

    return text;
}

Usage:

public const string MyConstantString = "Replace {thisText} with {otherText}";
MyConstantString.ReplaceText("first parameter", "second parameter");

The above result will be "Replace first parameter with second parameter".

Upvotes: 0

sumit sharma

Reputation: 127

Little bit modifying the answer of @Milosz Krajewski

(?<=\{)[^}{]*(?=\})

this will skip the middle single opening and closing Curly braces in the string.

Upvotes: 1

RajeshValangaiman

Reputation: 27

It is regex for C# .net.

@"{(.*?)}"

it display a

token1 token2

Upvotes: 1

Wiktor Stribiżew

Reputation: 626826

In C#, as in many other programming language, the regex engine supports capturing groups, that are submatches, parts of substrings that match a whole regex pattern, defined in a regex pattern with the help of parentheses (e.g. 1([0-9])3 will match 123 and save the value of 2 into a capture group 1 buffer). Captured texts are accessed via Match.Groups[n].Value where n is the index of the capture group inside the pattern.

Capturing is much more effecient that lookarounds. Whenever there is no need for complex conditions, capturing groups are much better alternatives.

See my regex speed test performed at regexhero.net:

Now, how can we get the substring inside curly braces?

if there is no other curly braces inside, with a negated character class: {([^{}]*)
if there can be nested curly brackets: {((?>[^{}]+|{(?<c>)|}(?<-c>))*(?(c)(?!)))

In both cases, we match an opening {, and then match (1) any character other than { or }, or (2) any characters up to the first paired }.

Here is sample code:

var matches = Regex.Matches("Test {Token1} {Token 2}", @"{([^{}]*)");
var results = matches.Cast<Match>().Select(m => m.Groups[1].Value).Distinct().ToList();
Console.WriteLine(String.Join(", ", results));
matches = Regex.Matches("Test {Token1} {Token {2}}", @"{((?>[^{}]+|{(?<c>)|}(?<-c>))*(?(c)(?!)))");
results = matches.Cast<Match>().Select(m => m.Groups[1].Value).Distinct().ToList();
Console.WriteLine(String.Join(", ", results));

Result: Token1, Token 2, Token1, Token {2}.

Note that RegexOptions.IgnoreCase is redundant when you have no literal letters that can have different case in the pattern.

Upvotes: 16

bunjeeb

Reputation: 1155

Thanks Milosz Krajewski, Nothing to add but here is the function

private List<String> GetTokens(String str)
{
    Regex regex = new Regex(@"(?<=\{)[^}]*(?=\})", RegexOptions.IgnoreCase);
    MatchCollection matches = regex.Matches(str);

    // Results include braces (undesirable)
    return matches.Cast<Match>().Select(m => m.Value).Distinct().ToList();
}

Upvotes: 5