CODEWITHSUNDEEP
bashunix
DrKumar
DrKumar

Reputation: 113

Bash script to compare/search two directories using file list as variable

I am trying to write a bash script that will allow me to grab the names of files on Dir1 for example, and use EACH file name as my search string in the find command, and run the find command on Dir2. Then, output the search results to a text file.

So, for example, when it runs it will:

Get files in Dir1:

  • file1.txt
  • file2.txt
  • file3.txt
  • file4.txt

Find any files in Dir2 with "file1" in name

file1 exists in Dir2 as "file1-extrafile.txt"

Write result to text file

Repeat using "file2" as search string.

How can I do this? Will diff help me? A for loop?

Upvotes: 1

Views: 3805

Answers (3)

antak
antak

Reputation: 20869

find Dir1 -type f -printf '%f\0' | xargs -0 -n1 find Dir2 -name

Given files:

Dir1/a/b/c
Dir1/a/d
Dir1/e

Dir2/a/b
Dir2/a/e
Dir2/d
Dir2/c
Dir2/e/f

Will print:

Dir2/c
Dir2/d
Dir2/a/e
Dir2/e

Upvotes: 1

Emil Sit
Emil Sit

Reputation: 23562

Put this in a file (say search.sh) and execute it with ./search.sh dir1 dir2

#!/bin/sh

dir1=$1
dir2=$2
[ -z "$dir1" -o -z "$dir2" ] && echo "$0 dir1 dir2" 1>&2 && exit 1

#
# Stash contents of dir2 for easy searching later
#
dir2cache=/tmp/dir2.$$
# Clean up after ourselves
trap "rm -f $dir2cache" 0 1 2 15
# Populate the cache
find $dir2 -type f > $dir2cache

#
# Iterate over patterns and search against cache
#
for f in $(find $dir1 -type f); do
    # Extract base name without extension
    n=$(basename $f .txt)
    # Search for files that begin with base name in the cache
    fgrep "/$n" $dir2cache
done

Upvotes: 0

Ansgar Wiechers
Ansgar Wiechers

Reputation: 200523

Try this:

for f in /dir1/*; do
  n=$(basename "$f")
  ls -1 /dir2/*${n%.*}*.${n##*.}
done > result.txt

Upvotes: 1

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