CODEWITHSUNDEEP
php
Mathias Lykkegaard Lorenzen
Mathias Lykkegaard Lorenzen

Reputation: 15886

Optional parameters aren't truly optional

I would like to have real optional parameters in PHP. I realize that I can do something like this:

function my_function($req_var, $opt_var1 = 90, $opt_var2 = "lala") {
    die("WEEEEEEEE!");
}

However, if I want to only specify the value of $opt_var2, I still must specify a value for $opt_var1.

Here's an example.

my_function("lala", 90, "omg");

In other words, I have to explicitly write 90 as $opt_var1 even though it's only $opt_var2 that I want to change.

Is it possible to do something like this?

my_function("lala", default, "omg");

That would be so helpful.

Upvotes: 3

Views: 87

Answers (3)

Adder
Adder

Reputation: 5868

You can use a parameter that is an associative array and extract it:

function func($options= array()) {
    $option1= "default value";
    ..
    extract($options);
    ..
}

Upvotes: 2

BlitZ
BlitZ

Reputation: 12168

There is a way with array parameters:

function my_func(array $params = array()){
    $arg1 = isset($params['one']) ? $params['one'] : 'default';
    $arg2 = isset($params['two']) ? $params['two'] : 'default';
    $arg3 = isset($params['three']) ? $params['three'] : 'default';

    // ...
}

Upvotes: 3

Your Common Sense
Your Common Sense

Reputation: 157839

function my_function($req_var, $opt_var1 = NULL, $opt_var2 = NULL) {
    if ($opt_var1 === NULL) {
        $opt_var1 = 90;
    }
    if ($opt_var2 === NULL) {
        $opt_var2 = "lala"
    }
}
my_function("lala", NULL, "omg");

Upvotes: 6

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