Perl -e and print $_

Question

I have a loop similar to :

if ( -e "$hash->{'key'}/filename" ) {
    print $_
}

I though $_ would refer to the argument of '-e' but that is not the case. Any special variable I could use here?

Answer 1

You can assign to a variable inside the test:

if ( -e (my $_ = "...")) {
  print;
}

-e will test on $_ if no argument is given, but it does not assign its argument to $_. To learn more about filetest operators, read the perlfunc entry.