CODEWITHSUNDEEP
pythonsqlalchemyattributeerror
Bleeding Fingers
Bleeding Fingers

Reputation: 7129

AttributeError while querying: Neither 'InstrumentedAttribute' object nor 'Comparator' has an attribute

The following code:

Base = declarative_base()
engine = create_engine(r"sqlite:///" + r"d:\foo.db",
                       listeners=[ForeignKeysListener()])
Session = sessionmaker(bind = engine)
ses = Session()

class Foo(Base):
    __tablename__ = "foo"
    id = Column(Integer, primary_key=True)
    name = Column(String, unique = True)

class Bar(Base):
    __tablename__ = "bar"
    id = Column(Integer, primary_key = True)
    foo_id = Column(Integer, ForeignKey("foo.id"))

    foo = relationship("Foo")


class FooBar(Base):
    __tablename__ = "foobar"
    id = Column(Integer, primary_key = True)
    bar_id = Column(Integer, ForeignKey("bar.id"))

    bar = relationship("Bar")



Base.metadata.create_all(engine)
ses.query(FooBar).filter(FooBar.bar.foo.name == "blah")

is giving me this error:

AttributeError: Neither 'InstrumentedAttribute' object nor 'Comparator' object associated with FooBar.bar has an attribute 'foo'

Any explanations, as to why this is happening, and guidance to how such a thing could be achieved?

Upvotes: 91

Views: 86952

Answers (6)

Samuel RIGAUD
Samuel RIGAUD

Reputation: 1702

This is a simple working example with multiple relations to the same table. This generally avoid having the error AttributeError while querying: Neither 'InstrumentedAttribute' object nor 'Comparator' has an attribute

def get_company(db: Session, company_id: int):
    best_contact = aliased(User, name="best_contact ")
    other_contact = aliased(User, name="other_contact")
        
    row = (
        db.query(Company, best_contact, other_contact)
        .join(best_contact, Company.best_contact_id == best_contact.id)
        .join(other_contact, Company.other_contact_id == other_contact.id)
        .filter(Company.id == company_id)
        .first()
    )
    return row

Upvotes: 2

Evgenii
Evgenii

Reputation: 3420

stmt = (
   select(Bar.id).
   where(Bar.foo.has(Foo.name=="test"))
)

Maybe it will be useful... I found it here: https://docs.sqlalchemy.org/en/14/tutorial/orm_related_objects.html#exists-forms-has-any

Upvotes: 2

ostrokach
ostrokach

Reputation: 19932

This is because you are trying to access bar from the FooBar class rather than a FooBar instance. The FooBar class does not have any bar objects associated with it--bar is just an sqlalchemy InstrumentedAttribute. This is why you get the error:

AttributeError: Neither 'InstrumentedAttribute' object nor 'Comparator' object associated with FooBar.bar has an attribute 'foo'

You will get the same error by typing FooBar.bar.foo.name outside the sqlalchemy query.

The solution is to call the Foo class directly:

ses.query(FooBar).join(Bar).join(Foo).filter(Foo.name == "blah")

Upvotes: 116

tokenizer_fsj
tokenizer_fsj

Reputation: 1240

I was getting the same error Neither 'InstrumentedAttribute' object nor 'Comparator' has an attribute, but in my case, the problem was my model contained a Column named query, which was overwriting the internal property model.query.

I decided to rename that Column to query_text and that removed the error. Alternatively, passing the name= argument to the Column method would have worked: query = db.Column(db.TEXT, name='query_text').

Upvotes: 12

Bleeding Fingers
Bleeding Fingers

Reputation: 7129

I cannot explain technically what happens but you can work around this problem by using:

ses.query(FooBar).join(Foobar.bar).join(Bar.foo).filter(Foo.name == "blah")

Upvotes: 40

qris
qris

Reputation: 8162

A related error that can be caused by configuring your SQLAlchemy relationships incorrectly:

AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'corresponding_column'

In my case, I incorrectly defined a relationship like this:

namespace   = relationship(PgNamespace, id_namespace, backref="classes")

The id_namespace argument to relationship() should just not be there at all. SQLAlchemy is trying to interpret it as an argument of a different type, and failing with an inscrutable error.

Upvotes: 2

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