CODEWITHSUNDEEP
phphtml
Victor
Victor

Reputation: 478

Echo something from script to html

I'm a noob in php and I need some help please. I have a uploading script that uploads something to my server. So after I upload the file i get a message your file was upload and I want this message to be posted in my html upload page(main page) and the code is like this:

     if(empty($errors)===true){
            move_uploaded_file($file_tmp,"upload/".$file_name);
            echo "Your file was upload!"; <- I want this line to be printed in other page //
        }else{
            print_r($errors);
        }
}

Edit : And I found an error to my script if you could help me with this two please:

$file_name=$_FILES['file']['name'];
$file_tmp =$_FILES['file']['tmp_name'];
$file_type=$_FILES['file']['type'];   
$file_ext=strtolower(end(explode('.',$_FILES['file']['name'])));

$extensions = array("rar","zip","jpeg","jpg","png","gif");
if(in_array($file_ext,$extensions)=== false){
$error[]= "Extension not allowed, please choose a RAR or ZIP file or if you upload an image use JPEG, JPG, PNG or GIF format.</br> Thank you!"; 
}

This is my code to restrict file upload,but it won't take the restrictions,can any1 tell me why please?

Hope I'm explicit enough. Thank you !

Upvotes: 0

Views: 86

Answers (2)

Abhishek Saha
Abhishek Saha

Reputation: 2564

You can modify your script in the below way.

... if(empty($errors)===true){
            move_uploaded_file($file_tmp,"upload/".$file_name);
            header("Location: otherpage.php?msg=success");            
        }else{

            header("Location: otherpage.php?msg=failure");  
            print_r($errors);
        }
} ...

In otherpage.php,

if(isset($_GET['msg']) && $_GET['msg'] == 'success') {

        echo "File uploaded sucessfully";

     }

EDIT:

You have written print_r($errors). I am assuming that $errors is an array. In that case you can pass this variable to the url by using json_encode($errors), see below.

$err = json_encode($errors);
$urlEncode = urlencode($err);
//now pass this to the url like this
header("Location: otherpage.php?msg=failure&err=".$urlEncode);  

//in otherpage.php, you have to decode it.
if(isset($_GET['err'])) {

    $errDecode = urldecode($_GET['err']);
    $err = json_decode($errDecode);
    print_r($err); //prints the error
}

Extensions:

Your script seems to be correct, can you try it in the below way.

$extensions = array("rar","zip","jpeg","jpg","png","gif");
  if(!in_array($file_ext,$extensions)){
  $error[]= "your error statement"; 
}

Upvotes: 1

Jerome Baldridge
Jerome Baldridge

Reputation: 518

Place your echo on the page you want it to appear on, not on a separate page. Alternately send your echo string as part of the form submission, but this is probably not appropriate for this case. But then you could set what should be printed on the next page, but set it in advance.

Upvotes: 0

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