Reputation: 1449
So here is a sample code :
import java.util.Scanner;
public class Test {
public static void main(String[] args) {
System.out.println("Please type in a number");
Scanner in = new Scanner(System.in);
switch (in.nextInt()){
case 1:
save(in);
break;
case 2:
System.out.println(value);
break;
default:
System.out.println("Default case");
break;
}
in.close();
}
public static String save(Scanner in){
System.out.println("Type in a word");
String value = in.next();
return value;
}
}
In this particular situation all I am trying to do here is to have access to the value
that was stored in case 1.
Upvotes: 0
Views: 4611
Reputation: 115378
switch
statement in all c-like languages including java is very general. It jumps to label according to the value of switch variable and then continues until break
statement appears.
I am not sure what did you meant in your long explanation but in following example:
switch(op) {
case ONE:
foo();
case TWO:
bar();
break;
case THREE:
aaa();
qqq();
break;
}
op == ONE
first method foo()
will be called, then the flow will arrive to block of TWO
because no break statement was written in ONE
, so bar()
will be called. However then the break statement will jump the flow to code that appears just after the switch.
This is a short explanation. For more details find a good book or tutorial and read chapter about switch statement.
Upvotes: 1