Reputation: 134
<?php
$q = mysql_query("SELECT sub_cat.*, links.*
FROM links
LEFT JOIN sub_cat
ON links.p_id = sub_cat.id
WHERE sub_cat.p_id = '$id'
ORDER BY name ASC") or die (mysql_error());
while ($r = mysql_fetch_assoc($q))
{
$links_name = $r['name'];
$link_h3 = $links_name != '' ? '<h3>' . $links_name . '</h3>' : '';
//print $link_h3;
print '<pre>';
print_r ($r);
}
?>
I have two tables with rows like:
In sub cat i have movie categories, like foreign language movies, national movies, uncategorised movies and so on. In links table i have concrete movie links and depending on sub category.
The only thing is that i do not want dublicate titles (sub_cat.name). result is:
Without Category www.moviesite.com
Without Category www.moviesite2.com
Without Category www.moviesite3.com
Foreign Movies www.moviesite1.bla
Foreign Movies www.moviesite2.bla
I want to be
Without Category www.moviesite.com
www.moviesite2.com
www.moviesite3.com
Foreign Movies www.moviesite1.bla
www.moviesite2.bla
and do not have any idea how to do this :(
any help appreciated.
Upvotes: 1
Views: 16803
Reputation: 3534
To do the job, you have 2 solutions:
The first solution is to process your data before showing it, in order to group all movies by category.
You can do for example:
$moviesByCategory = array();
while ($r = mysql_fetch_assoc($q))
{
// Create the new sub array for the new category if necessary
if (!isset($moviesByCategory[$r['name']]))
$moviesByCategory[$r['name']] = array();
// Add the movie in the category
$moviesByCategory[$r['name']][] = $r['links'];
}
And then, you can now iterate on this new array like
foreach($moviesByCategory as $category => $movies)
{
// Print the category name
echo '<h1>' . $category . '</h1>';
// Print all movies of the category
foreach($movies as $movie)
echo '<h3>' . $movie . '</h3>';
}
The second solution is to modify the SQL query to group directly all movies that have the same category. You just have to use a GROUP BY
clause on sub_cat.id
and then apply an agregate function on all other fields in the select.
For performance aspect, the best solution is the SQL solution, but doing it with PHP will give you more flexibility for the presentation.
Upvotes: 2
Reputation: 144
Try something like:
$lastSubcatName = "";
while ($r = mysql_fetch_assoc($q))
{
$links_name = $r['name'];
if($lastSubcatName != $links_name)
{
echo "<h1>".$links_name."</h1>";
$lastSubcatName = $links_name;
}
echo '<h3>' . $r['links'] . '</h3>';
}
Upvotes: -1