CODEWITHSUNDEEP
shell
Aparna
Aparna

Reputation: 123

Bash syntax error: unexpected end of file with for loop

#!/bin/bash

cp ./Source/* ./Working/ 2> /dev/null
echo "Done"


for filename in *.zip;do unzip “$filename”;
 done

In the above script, I am trying to copy all the files from source to working and unzip the files in working folder but I am geting igetting an error unexpected end of file

Upvotes: 1

Views: 1304

Answers (2)

cogsmos
cogsmos

Reputation: 836

You have up to two problems here. First you quotes are not standard. You probably copy pasted from MS Word or something that automatically converts quotes.

The second problem you may have is that your filenames may have spaces in it. This can cause all sorts of problems in scripts if you do not expect it. There are a few workarounds but the easiest is probably to change the IFS:

OLDIFS=$IFS
IFS="$(echo -e '\t\n')" # get rid of the space character in the IFS
... do stuff ...
IFS=$OLDIFS

Upvotes: 0

Jens
Jens

Reputation: 72639

It looks like you have different kinds of double quotes in "$filename", make sure both are ASCII double quotes (decimal 34, hex 22). Try analyzing your script with

 od -c scriptname

Upvotes: 3

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