Reputation: 610
I'm trying to get this to work:
template<class Type>
typename boost::enable_if< boost::mpl::or_<
boost::is_arithmetic<Type>,
is_string<Type> > >::type
get(const std::string &argPath, const Type &argDefault) {
bool caught = false;
std::stringstream ss;
Type value;
try {
value = ptree_.get<Type>(argPath);
} catch(ptree_bad_path &e) {
caught = true;
}
if(caught)
value = argDefault;
ss << value;
parameters_.insert(std::pair<std::string, std::string>(argPath, ss.str()));
return value;
}
I used the following is_string type trait: Type trait for strings
My goal is to restrict my Type
to string or arithmetic type so that I can push it to my stringstream
.
So this builds, but when I try to use it, it returns the following errors:
error: void value not ignored as it ought to be
In member function ‘typename boost::enable_if, is_string, mpl_::bool_, mpl_::bool_, mpl_::bool_ >, void>::type FooClass::get(const std::string&, const Type&) [with Type = uint8_t]’
error: return-statement with a value, in function returning 'void'
Here is how I try to use it:
FooClass f;
item_value = f.get("tag1.tag2.item", DEFAULT_ITEM_VALUE);
Any help is appreciated, thanks in advance!
Upvotes: 0
Views: 199
Reputation: 7202
From http://www.boost.org/doc/libs/1_53_0/libs/utility/enable_if.html, enable_if
has a second parameter that defaults to void:
template <bool B, class T = void>
struct enable_if_c {
typedef T type;
};
Seems to me you need to include the return type in your enable_if. (It is defaulting to void now.)
template<class Type>
typename boost::enable_if< boost::mpl::or_<
boost::is_arithmetic<Type>,
is_string<Type> >,
Type >::type
get(const std::string &argPath, const Type &argDefault);
Upvotes: 4