CODEWITHSUNDEEP
androidstring
Sharjeel Siddique
Sharjeel Siddique

Reputation: 73

How to pass a double in .getText()

I'm trying to create an app that converts celsius to Farhenheit. I want to pass float in .getText() but I'm unable to do so, It is giving me error which say cannot invoke .getText() on the primitive time float. Like I want to take the user input as double and then do the maths calculation. Can you please suggest me the approach to achieve this.

    changer = Float.parseFloat(textIn.getText().toString());
          textOut.setText(changer);

Upvotes: 1

Views: 263

Answers (4)

Houcine
Houcine

Reputation: 24181

   float celsius = Float.parseFloat(textIn.getText().toString());
   float farhenheit = (celsius * 1.8f) + 32.0f;
   textOut.setText(""+farhenheit);

in the case of converting from farhenheit to celsius:

case(R.id.radioButton2):
 float farhenheit = Float.parseFloat(textIn.getText().toString());
       float celsius = (( farhenheit - 32.0f ) x 5.0f ) / 9.0f;
       textOut.setText(""+celsius);
         break;

NB : you should add break; at the end of each case in the switch bloc

Upvotes: 1

Django Steemans
Django Steemans

Reputation: 61

i am currently not able to test this but i think this is the answer u need

String text = edittext.gettext.toString()
double f = double.parseDouble(text);
double f2 = do the math to calculate farhenheit
textview.settext(f2.toString())

Upvotes: 0

Jibran Khan
Jibran Khan

Reputation: 3256

txtProt = (EditText) findViewById(R.id.Protein);
p = txtProt.getText().toString();
protein = Double.parseDouble(p);

Upvotes: 2

saravanan
saravanan

Reputation: 388

First you want edittext.gettext().tostring. And String Convert to double.

Upvotes: 2

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