Reputation: 6820
I have a question about using data (obtained in PHP) in Javascript. This is what I do for now:
file index2.html
<div class="container">
<form class="well">
<label>Your appid</label>
<input type="text" class="span3" id="appid" placeholder="Type your appid here..."> <br>
<button type="submit" id="submit" class="btn btn-primary" data-loading-text="Loading..." >Submit</button>
</form>
<p id="errors" class="text-error"></p>
</div> <!-- /container -->
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script>window.jQuery || document.write('<script src="js/vendor/jquery-1.9.1.min.js"><\/script>')</script>
<script src="js/main.js"></script>
file main.js
$(document).ready(function() {
// CLICK ON SUBMIT BUTTON
$("#submit").click(function(e) {
// stop form submission first
e.preventDefault();
var btn = $(this);
btn.button('loading');
// GET VALUE OF APPID
var appid = $("#appid").val();
if (isNaN(appid))
{
alert("Only numbers allowed!");
}
else
{
// GET JSON FROM PHP SCRIPT
$.ajax({
type: 'GET',
url: 'loadjson.php',
data: {
'appid': appid
},
success: function (data) {
var object = JSON.parse(data);
checkCompletion(object);
},
error: errorHandler
});
}
}); // END OF CLICK FUNCTION
}); // END OF DOCUMENT READY
As you can see I make an AJAX call to loadjson.php!
file loadjson.php
<?php
if(isset($_GET['appid']) && !empty($_GET['appid'])) {
$appid = $_GET['appid'];
}
$json_url ='http://api.tapcrowd.com/api/gateway/call/1.4/getApp?appid=' . $appid;
$ch = curl_init($json_url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$str = curl_exec($ch);
curl_close($ch);
$data = json_decode($str);
$array = json_encode($data);
echo $array;
?>
Now I have the question if there is a possibility that I don't need to make an AJAX call but maybe I can have PHP in my HTML file and use it in my Javascript?
Does anyone know if this is possible and so yes, how?
Upvotes: 0
Views: 342
Reputation: 7653
If your html document extension is .php then yes you can simply use
var phpValue = "<?=$yourVariable?>";
Assuming that all json_encode
and other functionalities are done on $yourVariable before its being used.
Upvotes: 1