CODEWITHSUNDEEP
androidtwitteroauth-2.0
Saad
Saad

Reputation: 309

How to use applicaiton-only oauth in twitter?

Can anyone show me how to use the application-only oauth in twitter? I have to implement it in my app but i cant find ANY tutorials on net for the new api 1.1. An example would be much better...

Upvotes: 1

Views: 843

Answers (1)

Abdullah
Abdullah

Reputation: 8995

Hi the following code include how to use application-only OAuth and get user_timeline.

  1. download this library http://loopj.com/android-async-http/

  2. use this code

    /*
 * -url user_timeline 
 * -client and asyncHttpResponseHandler is used to get timeline
 */
String url = "https://api.twitter.com/1.1/statuses/user_timeline.json?screen_name=<NAME>";
AsyncHttpClient client = new AsyncHttpClient();
AsyncHttpResponseHandler asyncHttpResponseHandler = new AsyncHttpResponseHandler() {

  public void onSuccess(String response) {
     /*--------- DidReceiveData ---------*/
     Log.e("", "JSON FILE "+" response " + response);
  };
};

/*
 * OAuth Starts Here
 */
RequestParams requestParams = new RequestParams();
requestParams.put("grant_type", "client_credentials");
AsyncHttpClient httpClient = new AsyncHttpClient();
httpClient.addHeader("Authorization", "Basic " + Base64.encodeToString((CONSUMER_KEY + ":" + CONSUMER_SECRET).getBytes(), Base64.NO_WRAP));
httpClient.addHeader("Content-Type", "application/x-www-form-urlencoded;charset=UTF-8");
httpClient.post("https://api.twitter.com/oauth2/token", requestParams, new AsyncHttpResponseHandler() {

        public void onSuccess(String responce) {

            try {
                JSONObject jsonObject = new JSONObject(
                        responce);
                Log.e("", "token_type " + jsonObject.getString("token_type") + " access_token " + jsonObject.getString("access_token"));
                client.addHeader("Authorization", jsonObject.getString("token_type") + " " + jsonObject.getString("access_token"));
                client.get(url, asyncHttpResponseHandler);
            } catch (JSONException e) {
                e.printStackTrace();
            }
        };

        public void onFailure(Throwable error, String response) {
            Log.e("", "error " + error.toString() + " response " + response);

        };

    });

Upvotes: 1

Related Questions