CODEWITHSUNDEEP
pythonexcelpython-2.7automationpywin32
northix
northix

Reputation: 65

Call a macro with parameters : Python win32com API

What I want to do is call a macro from my python code. Here isa sample of the sources :

xl = win32.gencache.EnsureDispatch('Excel.Application')
xl.Visible = 1
xl.Workbooks.Open("C:\\Program Files\\Microsoft Office\\Office14\\XLSTART\\perso.xlsm")
xl.Workbooks.Open(argv[1])
xl.Application.Run('perso.xlsm!' + argv[2])
xl.Application.Run('perso.xlsm!' + argv[2] + '2')
xl.Workbooks.Open(argv[0])
xl.Application.Run('perso.xlsm!aggregate_report_ouverture_appli')
xl.Application.Run('perso.xlsm!macro', 'lol')
xl.Save()
xl.Quit()

The first two macro are working fine. But the last need a parameter to be set ("lol" in this case). With this try :

xl.Application.Run('perso.xlsm!macro', 'lol')

My macro is call but the parameter is not set. Any idea how to do this or where I can find the "javadoc" of this module (yeah i am from Java world !).

If you need more explanations just le me know.

Thanks you.

Damien.

Upvotes: 3

Views: 13452

Answers (1)

Radical Edward
Radical Edward

Reputation: 5504

Unfortunately in this case, the complete documentation for win32com with regards to excel does not exist; you will have to look at the MS office Excel MSDN for most everything (which isn't too bad you just have to finagle the code sometimes):

http://msdn.microsoft.com/en-us/library/office/bb149081(v=office.12).aspx

As for your question, consider the example macro which takes two parameters:

Sub Proc(sParam1 As String, iParam2 As Integer)
        MsgBox sParam1 & " is " & iParam2 & " Years Old"
End Sub

The macro has two parameters that it's looking for. The following python code will call the macro using the params set:

import win32com.client
xl=win32com.client.Dispatch("Excel.Application")
xl.Visible = True
Path = "C:\\Program Files\\Microsoft Office\\Office14\\XLSTART\\perso.xlsm"
xl.Workbooks.Open(Filename=Path)
param1 = "Jeremy"
param2 = 3
xl.Application.Run("Proc", param1, param2)

I'm not sure what variable type the macro in your case is expecting, but 'lol' is but it is being sent to the macro from python as a string in your example. Hope this helps.

Upvotes: 4

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